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tankabanditka [31]
2 years ago
6

If a man drives 600km from Johannesburg to Durban. He starts his journey with a full tank of petrol. If the man drives at an ave

rage speed of 120 km/h, how long would the journey take? ​
Mathematics
1 answer:
arlik [135]2 years ago
7 0

Answer:

I think it's 5

Step-by-step explanation:

im not sure

but correct me if I'm wrong

You might be interested in
If Jun has 12 t-shirts, 6 pairs of pants, and 3 pair of shoes how many ways can he dress himself up for the day?
Serjik [45]
12 x 6 x 3 =216. He can dress himself up in 216 different ways. 

I hope this helps!
6 0
4 years ago
Given the vector (4|3) and the transformation matrix (0|1|-1|0), which vector is the imagine after applying the transformation t
horrorfan [7]

Answer:

C.(3|-4)

Step-by-step explanation:

Given the vector:

\left[\begin{array}{ccc}4\\3\end{array}\right]

The transformation Matrix is:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]

The image of the vector after applying the transformation will be:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right]

The correct option is C

7 0
4 years ago
PLS HELP I WILL DO ANYTHING
Lunna [17]

Answer:

the solution for x is x=40

4 0
3 years ago
Find the minimum or maximum value of the function g(x)= -(x-2)^2-3
Nady [450]
Neato

assuming you mean
g(x)=-1(x-2)^2-3
remember
in form
f(x)=a(x-h)^2+k
a is leading coficient
(h,k) is vertex
k will be the minimum or max value of the function
if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max

given
g(x)=-1(x-2)^2-3
a is negative
the parabola opens down and k is the max value
it is -3
the max value is -3, which occors at x=2
g(2)=-3 is max
3 0
3 years ago
Max <br> p=3x+2y <br> subject to <br> 5x+y&lt;16 <br> 2x+3y&lt;22 <br> x&gt;0 <br> y&gt;0
garri49 [273]

Answer:For all the corner points, the maximum is at point (1, 3)

From the graph of the constraints, the corner points of the feasibility region are (0, 0), (0, 10/3), (1, 3), (2, 0)

For (0, 0): p = 0 + 2(0) = 0

For (0, 10/3): p = 0 + 2(10/3) = 20/3 = 6.67

For (1, 3): p = 1 + 2(3) = 1 + 6 = 7

For (2, 0): p = 2 + 2(0) = 2

Therefore, solution = (1, 3)

3 0
3 years ago
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