Suppose the matrix representing a system of difference equations contains a row of zeros. What does this imply about the system?

Mathematics

1 answer:

MAXImum [283]3 years ago

4 0

Answer:

dimension-crushing transformation.

Step-by-step explanation:

A dimension-crushing transformation represents a matrices of all zero vector element in it (row or column).

For instance, a three-dimensional matrix with an all zero row will take three-dimensional vectors.

A dimension-crushing transformation matrices have no inverse.

we can as well conclude that the corresponding matrices have a determinant of zero (and it's obvious from the way the determinant is calculated that this is so for matrices that are cross-cut by an all-zero row or column).

So all of this gives you a whole new geometric view on systems of linear equations.

reference: https://math.stackexchange.com/

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Avaluate 2^3x-1 for x=1

DENIUS [597]

Answer:

4 or 7 (Check the explanation to see which one your equation actually is.

Step-by-step explanation:

One thing I want to clarify for you, It's Evaluate, not Avaluate.

Okay so, we want to find the value of 2^3x-1 and we know x = 1.

You didn't really clarify if the expression was $2^{3x-1}$ or $2^{3x}-1$ , so I'll be doing both:

For $2^{3x-1}$ , we should plug in x to get $2^{3(1)-1}$ and then simplify to get $2^{2}$ .

2 to the power of 2 or $2^{2}$ is equal to 2 * 2 or 4.

The second one, $2^{3x}-1$ , we should plug in x to get $2^{3(1)}-1$ and then to become $2^{3}-1$ . 2 to the power of 3 or $2^{3}$ is 8 and then minus 1 is 7.