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kherson [118]
3 years ago
9

It is a good practice to use 3d to plot a single dimensional data in storytelling.

Computers and Technology
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

The answer is "Option B".

Explanation:

The 3-dimensional diagrams also known as a 3D graph, it implies to 3D design, which Occasionally receives the 2D data, which effects 3D and It is a terrible form.

  • The whole additional dimension comes to an end but never more than inserting a chart or its readability could be dramatically affected.
  • It uses the 3D to create a single dimension, but the information is not a great training.
You might be interested in
Create a lottery game application. Generate three random numbers (see Appendix D for help in doing so), each between 0 and 9. Al
Pachacha [2.7K]

The question is not complete! Here is the complete question and its answer!

Create a lottery game application. Generate three random numbers (see Appendix D for help in doing so), each between 0 and 9. Allow the user to guess three numbers. Compare each of the user’s guesses to the three random numbers and display a message that includes the user’s guess, the randomly determined three-digit number, and the amount of money the user has won as follows:

no matches: 0

any one matching: 10$  

two matching: 1000$  

three matching: 100000$  

Code with Explanation:

#include <iostream>

using namespace std;

int main()

{

int matches=0;

int guess_1, guess_2, guess_3;

int num_1, num_2, num_3;

// get 3 digits from the user

cout<<"Enter first guess digit 0 to 9"<<endl;

cin>>guess_1;

cout<<"Enter second guess digit 0 to 9"<<endl;

cin>>guess_2;

cout<<"Enter third guess digit 0 to 9"<<endl;

cin>>guess_3;

// every time program runs srand() generates new random numbers and rand()%10 makes sure that number is single digit 0 to 9

srand(time(NULL));

num_1=rand()%10;

cout<<"First lottery digit: "<<num_1<<endl;

num_2=rand()%10;

cout<<"Second lottery digit: "<<num_2<<endl;

num_3=rand()%10;

cout<<"Third lottery digit: "<<num_3<<endl;

// store random generated numbers and guess numbers in arrays to compare them

int num[3]= {num_1,num_2,num_3};

int guess[3]={guess_1,guess_2,guess_3};

// compare the arrays to find out how many are matching

   for(int i=0; i<3; i++)

   {

 for(int j=0; j<3; j++)

 {

  if(num[i]==guess[j])

  {    

   matches = matches + 1;

  }

 }

}

cout << "Total Matches are: " <<matches << endl;

// display reward according to the number of matches

if (matches==0)

cout<<"you won: $0"<<endl;

if (matches==1)

cout<<"you won: $10"<<endl;

if (matches==2)

cout<<"you won: $1000"<<endl;

if (matches==3)

cout<<"you won: $100000"<<endl;

return 0;

}

Output:

Enter first guess digit 0 to 9

7

Enter second guess digit 0 to 9

1

Enter third guess digit 0 to 9

5

First lottery digit: 3

Second lottery digit: 7

Third lottery digit: 2

Total Matches are: 1

You won: $10

Enter first guess digit 0 to 9

7

Enter second guess digit 0 to 9

3

Enter third guess digit 0 to 9

4

First lottery digit: 5

Second lottery digit: 4

Third lottery digit: 7

Total Matches are: 2

You won: $1000

5 0
3 years ago
In one week, your company received the following quantities of e-mail messages. Monday 240 Tuesday 315 Wednesday 290 Thursday 18
Vika [28.1K]

Answer:

280

Explanation:

Average = (240 + 315 + 290 + 180 + 375) ÷ 5

= 1400 ÷ 5

= 280

Cheers

3 0
3 years ago
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
3 years ago
Jhon bought a new printer for his desktop computer. It does not work even though he checked all the cables and cords. What do yo
Roman55 [17]
I think it’s d sorry if it ain’t ..
4 0
2 years ago
Help me help you...........
lyudmila [28]

Answer:

the 4th answer

Explanation:

w stage for width, h for height.

6 0
2 years ago
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