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bixtya [17]
3 years ago
7

Calculate the solubility (in M) of cobalt(II) hydroxide, Co(OH)2(s) in H2O. Ksp = 1.10×10-16 at a specific temperature.

Chemistry
1 answer:
Oksanka [162]3 years ago
5 0

Answer:

3.018 x 10⁻⁶ M.

Explanation:

  • Co(OH)₂ dissociates in solution according to the equation:

<em>Co(OH)₂ →</em> <em>Co²⁺ + 2OH⁻.</em>

<em></em>

<em>∵ Ksp = [Co²⁺][OH⁻]² = (s)(2s)² = 4s³.</em>

<em />

∴ 4s³ = 1.10 x 10⁻¹⁶.

∴ s³ = 1.10 x 10⁻¹⁶/4 = 2.75 x 10⁻¹⁷.

∴ s = ∛(2.75 x 10⁻¹⁷) = 3.018 x 10⁻⁶ M.

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