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Mashutka [201]
3 years ago
8

A reaction that occurs when the reactants are simply put together is

Chemistry
1 answer:
Studentka2010 [4]3 years ago
3 0
Your answer would be a spontaneous reaction. Hope this helps!!
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I will give Brainliest and 30 points to whoever answers first!
Rom4ik [11]

3,5, and 1 i think maybe i uhm yeah

7 0
3 years ago
Each____<br> is a female sex organ about the size and<br> shape of an almond
Galina-37 [17]

Each \sf\purple{ovary} is a female sex organ about the size and shape of an almond.

Explanation:-

  • Ovaries are the the primary female reproductive organs.
  • There are two ovaries which are located on either side of the uterus.
  • The two functions of ovaries are -i) to produce eggs (ova) and ii) to produce female hormones.

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6 0
3 years ago
Balance the following equation __N2+__O2→__N2O​
kakasveta [241]

Answer:

2N2+02>_2N20

Explanation:

u have to use rap formula

4 0
3 years ago
Suppose you need 0.12L of a 0.13M solution of NiCl2, but all you have is a solution that is a solution that is 0.23M. What volum
topjm [15]

- 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

The dilution problem uses the equation :

M_aV_a= M_bV_b

The initial molarity (concentration) M_a = 0.13 M

The initial volume V_a = 0.12 L

The desired molarity (concentration) M_b = 0.23 M

The volume of the desired solution V_b = ( 0.12 + x L )

Substituting values in above equation;

(0.13 M ) (0.12 L) = (0.23 M ) (0.12 L + x L)

0.0156 M L = 0.0276 M L + 0.23 x M L

- 0.012 M L = 0.23 x M L

x = - 0.05

Therefore, - 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

Learn more about molarity here:

brainly.com/question/26873446

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3 0
2 years ago
1) How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7g Fe? Show your work.
klasskru [66]
1.) is157.7 g
<span>moles Fe = 209.7 g/ 55.847 g/mol=3.75 
the ratio between Fe and CO is 2 : 3 
moles CO = 3.75 x 3 /2 =5.63 
mass CO = 5.63 mol x 28.01 g/mol=157.7 g

2.) is </span><span>1.06 moles 
</span>48.7/23 = 2.12 moles sodium 
<span>2.12/2 x 24 = 25.44dm^3 hydrogen = 1.06 moles </span>
1.06 X 6.02x10^23 = 1.204x10^24 molecules of hydrogen.

3.) is 91.8 
<span>8.3 moles H2S x (2 moles H2O / 2 moles H2S) = 8.3 moles H2O = theoretical amount produced. </span><span>8.3 moles H2O x (18.0 g H2O / 1 mole H2O) = 149 g H2O produced theoretically. </span><span>% yield = (actual amount produced / theoretical amount) x 100 = (137.1 g / 149 g) x 100 = 91.8 </span>
6 0
3 years ago
Read 2 more answers
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