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wlad13 [49]
4 years ago
7

What is the volume of 0.1 mole of methane (CH4) ? (One mole of any gas occupies 22.4 L under certain conditions of temperature a

nd pressure. Assume those conditions for this question.)
2.2 L


20 L


22.4 L


44.8 L
Chemistry
2 answers:
Veronika [31]4 years ago
8 0

Answer:

Option A = 2.2 L

Explanation:

Given data:

volume of one mole of gas = 22.4 L

Volume of 0.1 mole of gas at same condition = ?

Solution:

It is known that one mole of gas at STP occupy 22.4 L volume. The standard temperature is 273.15 K and standard pressure is 1 atm.

For 0.1 mole of methane.

0.1/1 × 22.4 = 2.24 L

0.1 mole of methane occupy 2.24 L volume.

Firdavs [7]4 years ago
7 0

Answer:

2,2 L

Explanation:

Under normal conditions of temperature and pressure: 273 K and 1 atm. The formula is used:

PV= nRT

R= Regnault constant

1 atm x  V = 0,1mol x 0,082 l atm/K mol x 273 K

V = (0,1mol x 0,082 l atm/K mol x 273 K)/ 1 atm

V= 2,2368 l

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anzhelika [568]

Answer:

\boxed{\text{25. 20 L; 26. 49 K}}

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}

Calculations:

\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:  

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 ×  8.314 × T

2026 = 41.57T

T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}

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4 years ago
What is k in the rate law equation?
REY [17]

Answer:

B. A rate constant

Explanation:

The mathematical expression of rate law is given below,

Rate = K[A]m[B]n

This rate law show the relationship between the rate of chemical reaction and concentration of reactants.

In given equation [A] and [B] are molar concentration of reactants while K represent rate constant.

The value of K is specific for particular reaction at particular temperature,

m and n are represent exponents and determine experimentally. The value of K is not depend upon the concentrations of reactant but depend upon the surface area and temperature

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Your answer is C. Sublimation :)(

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Ostrovityanka [42]

Answer:

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Explanation:

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Answer:

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3) Gases fill their container, showing that gas particles are not tied together and can move far apart.

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