Answer:
The correct answer is option B.
Explanation:
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The equation for the ionization of the magnesium hydroxide is given as:
xS yS
Here, S = concentration of compound dissolved in solvent via dissociation
Expression for the solubility product of 
will be:
![K_{sp}=[A^{y+}]^x[B^{x-}]^y\\\\K_{sp}=(xS)^x\times (yS)^y](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BA%5E%7By%2B%7D%5D%5Ex%5BB%5E%7Bx-%7D%5D%5Ey%5C%5C%5C%5CK_%7Bsp%7D%3D%28xS%29%5Ex%5Ctimes%20%28yS%29%5Ey)
As we can see,
![K_{sp}\propto [S]](https://tex.z-dn.net/?f=K_%7Bsp%7D%5Cpropto%20%5BS%5D)
- Higher the value of [S] more will be solubility of compound in a solvent.Hence, more soluble it will be.
- Lower the value of [S] less will be solubility of compound in a solvent.Hence, less soluble it will be.
Hence, the correct answer is option B.
Answer:
yes
Explanation:
since humans dig out the earth for resources o believe that fossils far every species that exists and is extinct will be found and will be pieced together
You can wait until he either breaks up (if he does) or if just forget about him and go for another guy.
Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa
Explanation:
Pressure in the submarine = 108.9 kPa
Volume, V = 2.4 * 10^5 L
Pressure, P = 116k Pa
Temperature, T = 312 K
Ideal gas law: PV = nRT or n = PV / RT
So, moles of gas, n =116 KPa * 2.4 * 10 ^5L / 8.314 LK Pa K^-1 *312 K
= 1.073 *10^4 mol
when temperature is changed to 293K,
PV = nRT or P = nRT / V
=1.073 *10^4 mol *8.314 LK Pa mol^-1 K^-1 *293 K / 2.4*10^5L
=108.9 K Pa
Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa
C₄H₉OH + HBr = C₄H₉Br + H2O
Δmole of alcohol gives 1 mole of bromobutanol
HBr is in excess, so the yield of the product is limited by the alcohol
Wt. of 1 butanol = 18
Molar mass of the butanol = 74.12 g/mole
Moles of the alcohol = 1/74.12 = 0.01349 moles
So, moles of bromobutane = 0.01349 moles
Molar mass of C₄H₉Br = 137.018 g/moles
So, theoretical mass of bromobutane is = 0.01349 × 137.0.18
= 1.85 g
