Your answer would be 1.00$ because if you subtract all that is given from the problem you get 10-9, which equals 1.
sin(x+y)=sin(x)cos(y)-cos(x)sin(y)
also, remember pythagorean rule, 
given that sin(Θ)=4/5 and cos(x)=-5/13
find sin(x) and cos(Θ)
sin(x)
cos(x)=-5/13
using pythagorean identity
(sin(x))^2+(-5/13)^2=1
sin(x)=+/- 12/13
in the 2nd quadrant, sin is positve so sin(x)=12/13
cos(Θ)
sin(Θ)=4/5
using pythagrean identity
(4/5)^2+(cos(Θ))^2=1
cos(Θ)=+/-3/5
in 1st quadrant, cos is positive
cos(Θ)=3/5
so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)
sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)
sin(Θ+x)=16/65
answer is 1st option
Answer: Your answer is r^12t^12
Step-by-step explanation: You use the distribution property.
We are given two points: (-1, -1) and (1, -4). Slope is calculated as the change in y over the change in x, or rise over run.
The change in y is the difference of the two y coordinates (it doesn't matter the order): -1 - (-4) = 3
The change in x is the difference of the two x coordinates (this order depends on the order that you subtracted the y coordinates; they must be the same order): -1 - 1 = -2.
So, the slope is 3/-2