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Kaylis [27]
4 years ago
8

What is the length of a rectangle with with 20 inches it in area 114 in.2

Mathematics
1 answer:
KiRa [710]4 years ago
3 0
Length is 5.7 inches
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What is the mean absolute deviation?
Lostsunrise [7]

Answer:

0.8 cm

Step-by-step explanation:

The formula for MAD is attached in the picture.

x_i are the values (data)

x bar is the mean

n is the number of numbers (data)

For figuring out MAD, basically, <em>we subtract the mean from each of the values respectively and take the absolute value and SUM for all of the numbers in the data set. Then we divide by n, the number of numbers.</em>

<em />

Let's do this:

MAD = \frac{|2-3|+|2-3|+|2-3|+|2-3|+|3-3|+|3-3|+|3-3|+|4-3|+|4-3|+|5-3|}{10}\\=\frac{1+1+1+1+0+0+0+1+1+2}{10}\\=\frac{8}{10}=0.8

MAD is 0.8

6 0
3 years ago
Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

x_v=-\frac{b}{2a}

In this problem, we have:

y=-x^2-6x-13

Then:

a = -1

b = -6

We write now:

x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

-x^2-6x-13=0

To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

y=-0^2-6\cdot0-13=-13

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0
1 year ago
Please help me. What are the correct numbers in this photo?
Marta_Voda [28]

Answer:

5 : the number is divisible by 5 because the divider ends with a 5

3: the number is divisible by 3 because the sum of all the digits of the divider are visible by 3.

6 0
3 years ago
Please Help giving Brainliest1!! A die is rolled 16 times and the number that appeared for each roll was recorded. The results a
Gwar [14]
10. The numbers on the horizontal line would be:
1, 2, 3, 4, 5, 6

11. Count how many of each number there is.
1- 3
2- 4
3- 2
4- 3
5- 2
6- 2
So numbers 1 and 4 will both have 3 dots above them and numbers 3, 5, 6 will have 2 dots above them.

4 0
3 years ago
Which of the following choices are equivalent to the expression below? check all that apply
Naddika [18.5K]

The choices are equivalent to the expression correct choices are A, C, and D.

The given expression is

x^3 /5

<h3>What is the expression?</h3>

The expression consists of numbers and arithmetic operators. It does not contain equality or inequality symbols.

<h3>What is the power rule?</h3>

a^{\frac{m}{n} =\sqrt[n]{a^m}

Therefore the above power rule implies that,

x^{(\frac{3}{5}) }=\sqrt[5]{x^3}

Also, we have the power rule

(a^m)}^n=a^{mn}

x^{\frac{3}5} =(x^3)^{\frac{1}{5}

or it can be written as

x^{\frac{3}{5} =(\sqrt[5]{x})^3

The correct choices are A, C, D.

To learn more about the expression visit:

brainly.com/question/723406

#SPJ1

3 0
2 years ago
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