Check the picture below.
now, we're making an assumption that, the two blue shaded region are equal in shape, and thus if that's so, that area above the 14 is 6 and below it is also 6, 14 + 6 + 6 = 26.
so hmm if we simply get the area of the trapezoid and subtract the area of the yellow triangle and the area of the cyan triangle, what's leftover is what we didn't subtract, namely the shaded region.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ h=15\\ a=14\\ b=26 \end{cases}\implies A=\cfrac{15(14+26)}{2}\implies A=300 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\stackrel{trapezoid}{300}~~ - ~~\stackrel{yellow~triangle}{\cfrac{1}{2}(26)(9)}~~ - ~~\stackrel{cyan~triangle}{\cfrac{1}{2}(15)(6)}} \\\\\\ 300~~ - ~~117~~ - ~~45\implies 138\qquad \textit{blue shaded area}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h~~%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases~%5Chfill%20%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D15%5C%5C%20a%3D14%5C%5C%20b%3D26%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B15%2814%2B26%29%7D%7B2%7D%5Cimplies%20A%3D300%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Areas%7D%7D%7B%5Cstackrel%7Btrapezoid%7D%7B300%7D~~%20-%20~~%5Cstackrel%7Byellow~triangle%7D%7B%5Ccfrac%7B1%7D%7B2%7D%2826%29%289%29%7D~~%20-%20~~%5Cstackrel%7Bcyan~triangle%7D%7B%5Ccfrac%7B1%7D%7B2%7D%2815%29%286%29%7D%7D%20%5C%5C%5C%5C%5C%5C%20300~~%20-%20~~117~~%20-%20~~45%5Cimplies%20138%5Cqquad%20%5Ctextit%7Bblue%20shaded%20area%7D)
Answer:
k = 28
Step-by-step explanation:
12/k = 18/42
Cross multiply.
18k = 12 * 42
18k = 504
Divide both sides by 18.
k = 28
Answer:
Rate of change = -1
Step-by-step explanation:
Given:
f(x) = -½(x + 2)² + 5
Required:
Average rate of change from x = -3 to x = 1
Solution:
Rate of change = 
Where,
a = -3,
f(a) = f(-3) = -½(-3 + 2)² + 5 = -½(-1)² + 5 = 4.5
b = 1,
f(b) = f(1) = -½(1 + 2)² + 5 = -½(9) + 5 = 0.5
Plug in the values into the formula:
Rate of change = 
Rate of change = 
Rate of change = -1
Answer:
Well I figure you would use a ratio. we are given one when comparing 240 lbs to 180 calories for each mile:
240lbs/180calories = 1 mile
we.are.given another when saying a person. burns 36 calories in 1 mile. we don't know weight so we will say x lbs:
x/36calories = 1 mile
since they both equal 1 mile we know they are equal:
240/180 = 1 = x /36
we can get rid of the 1 in between and say:
240/180 = x/36
let's reduce first fraction
8/6 = x/36
cross multiply:
8*36 = 6x
divide both sides by 6
8*6 = x
x = 48
Step-by-step explanation:
D. 117
4(5)^2+2(5)+7
4(25)+(10)+7
100+10+7= 117
