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GrogVix [38]
3 years ago
7

What is the exact value for cos(-2

n="absmiddle" class="latex-formula">/3)?
This should be done without a calculator.
Please explain the process if possible.

Mathematics
1 answer:
RSB [31]3 years ago
5 0
Notice the picture below

see where that angle is?

check your Unit Circle for that value

also notice, that fractions of \pi are just like grabbing 180 degrees and splitting it, so one third of 180 or \pi is 180/3 or 60 degrees

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ANSWER:

\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4

STEP-BY-STEP EXPLANATION:

We have the following equation:

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The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\  \\ \sqrt{f^{-1}(x)}=x+4 \\  \\ f^{-1}(x)=(x+4)^2 \end{gathered}

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4

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