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alexandr402 [8]
2 years ago
11

how can you use distributive property to write an expression equivalent to the one given above? Use reasoning to explain how you

know the expressions are equivalent.
Mathematics
1 answer:
Anit [1.1K]2 years ago
8 0

The reason how the expression are equivalent given below:

<h3>What is Distributive Property?</h3>

Multiplying a number by a sum or difference is the same as multiplying by each number in the sum or difference and then adding or subtracting.

The Complete question is:

How can you use distributive property to write an expression equivalent to the one given above? Use reasoning to explain how you know the expressions are equivalent.

Distributive property represents distribute the outside number among the number or digits in parenthesis.

For Example: Solve the expression 7(20 + 3) using the distributive property of multiplication over addition.

When we solve the expression 7(20 + 3) using the distributive property,

we first multiply every addend by 7.

This is known as distributing the number 7 amongst the two addends and then we can add the products.

This means that the multiplication of 7(20) and 7(3) will be performed before the addition.

Hence,  7(20) + 7(3) = 140 + 21 = 161.

Learn more Distributive Property here:

brainly.com/question/5637942

#SPJ1

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Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

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4 years ago
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katovenus [111]

Answer:

A

Step-by-step explanation:

He traveled at a rate of 60MPH

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