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3 years ago

Melanie saves $20 every month in her savings account. She

Mathematics

1 answer:

OLga [1]3 years ago

8 0

Let x represent the amount of months she has been saving for.

20x - 60 = 280

Solve for x.

20x - 60 = 280

~Add 60 to both sides

20x - 60 + 60 = 280 + 60

~Simplify

20x = 340

~Divide 20 to both sides

20x/20 = 340/20

~Simplify

x = 17

Therefore, Melanie has saved for 17 months.

Best of Luck!

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3 years ago

The university is on a bearing of 050 degrees from the stadium and 300 degrees from the hospital. Mark the position of the unive

Licemer1 [7]

Answer:

Check Explanation

Step-by-step explanation:

The map isn't available, but, one can draw this bearings with the descriptions given

Angles for bearings are usually drawn, reading from the north direction.

A sketch of the described bearings and locations of the stadium, university and the hospital is presented in the attached image to this question.

For the sketch on the map.

On The map, draw a four-cardinal points' cross at the stadium draw a line from the bearing 050° from the stadium's four cardinal points' cross. Leave the line as it is.

Then, draw another four cardinal points' cross at the hospital and draw a line from the bearing 300° from the hospital's four cardinal points' cross.

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3 years ago

f the dean wanted to estimate the proportion of all students receiving financial aid to within 3% with 99% reliability, how many

Oksanka [162]

Answer:

n=1849

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Assuming that the proportion is estimated $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{2.58})^2}=1849$

And rounded up we have that n=1849

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3 years ago

Sanjay read 56 pages of his book this weekend. This is 35% of the pages in the book. How many total pages are in the entire book

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I don't know if I did this right.
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