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3 years ago

Lines a and b are parallel what is the value of a

Mathematics

1 answer:

kozerog [31]3 years ago

6 0

Step-by-step explanation:

if a+3=5 then

5-3=a

a=2

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Solve for the value of x. <br> 1.x+8=-10<br> 2.X-5=7<br> 3.5x=30<br> 4.X over 5 =-8

BabaBlast [244]

-18 negative eighteen
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12 positive twelve
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8 0

3 years ago

Find the missing height of the cone. Volume= 118π ft3 Diameter= 2/3

grin007 [14]

Answer:

11 ft

Step-by-step explanation:

The equation for the volume of a cone is:

V = 1/3(3.14)r^2h

V = 414.48

r = 6

Plug in those values and solve for h:

414.48 = 1/3(3.14)(6)^2h

414.48 = 37.68h ; divide both sides by 37.68

11 = h

The missing height is 11ft.

6 0

3 years ago

What is the surface area of the rectangular pyramid below?

Furkat [3]

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8 0

3 years ago

At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more

I am Lyosha [343]

Answer:

The probability is $P( X \le 4 ) = 0.0054$

Step-by-step explanation:

From the question we are told that

The percentage that are on time is p = 0.76

The sample size is n = 11

Generally the percentage that are not on time is

$q = 1- p$

$q = 1- 0.76$

$q = 0.24$

The probability that no more than 4 of them were on time is mathematically represented as

$P( X \le 4 ) = P(1 ) + P(2) + P(3) + P(4)$

=> $P( X \le 4 ) = \left n } \atop {}} \right.C_1 p^{1} q^{n- 1} + \left n } \atop {}} \right.C_2p^{2} q^{n- 2} + \left n } \atop {}} \right.C_3 p^{3} q^{n- 3} + \left n } \atop {}} \right.C_4 p^{4} q^{n- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{11- 1} + \left 11 } \atop {}} \right.C_2p^{2} q^{11- 2} + \left 11 } \atop {}} \right.C_3 p^{3} q^{11- 3} + \left 11 } \atop {}} \right.C_4 p^{4} q^{11- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{10} + \left 11 } \atop {}} \right.C_2p^{2} q^{9} + \left 11 } \atop {}} \right.C_3 p^{3} q^{8} + \left 11 } \atop {}} \right.C_4 p^{4} q^{7}$

$= \frac{11! }{ 10! 1!} (0.76)^{1} (0.24)^{10} + \frac{11!}{9! 2!} (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!} (0.76)^{3} (0.24)^{8} + \frac{11!}{7!4!} (0.76)^{4} (0.24)^{7}$

$P( X \le 4 ) = 0.0054$

4 0

3 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.

andrezito [222]

Answer:

Step-by-step explanation:

Since the output is just the input multiplied by 3, the output will be 15.4*3=46.2, or answer choice C. Hope this helps!

3 0

3 years ago

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