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3 years ago

Write the polynomial in standard form and identify the x-intercept, as well as the zeros for

1 answer:

7 0

Well, ok, the x intercepts aer where the function equals 0
also
if the x intercepts are r1 and r2 then the factored form of the function is
f(x)=a(x-r1)(x-r2) where a is a constant
well, we have it already in that form

f(x)=(x-3i)(x-3i)
the x intercept is at x=3i
standard form requires expansion
we expand to get
f(x)=x²-6i-9

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3 years ago

Which property is illustrated, 1n = n

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3 years ago

Find the equation of the directrix of the parabola found in part A.

elena-s [515]

The specific equation of the parabola can be found by plugging the given

values of the variables of the general equation.

<h3>Correct Response;</h3>

$\displaystyle The \ equation \ of \ the \ parabolic \ reflector \ is; \ \underline{ y = \frac{1}{12} \cdot x^2}$

<h3>Method used to obtain the above equation;</h3><h3 /><h3>Given parameters;</h3>

The vertex of the parabola is at the origin with coordinates (0, 0)

The location of the focus = 3 cm from the vertex

<h3>Required:</h3>

The equation that models the parabola.

<h3>Solution:</h3>

The vertex form of the equation of a parabola is y = a·(x - h)² + k

The above equation can be expressed as (x - h)² = 4·p·(y - k)

Where in a vertical parabola;

(h + p, k) = The coordinates of the focus

(h, k) = The coordinates of the vertex = (0, 0)

p = 3 = The distance of the focus from the vertex

Therefore, the coordinates of the focus = (0 + 3, 0) = (3, 0)

The equation of the parabola is therefore;

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Learn more about the equation of a parabola here:

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