Answer:
I would try 12.85
Step-by-step explanation:
7.75 + 5.1 = 12.85
if you moved TS down onto BL, it would fit, so add the value of LS and TS.
hope this helps :)
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the true population mean textbook weight.
Number of sample, n = 22
Mean, u = 64 ounces
Standard deviation, s = 5.1 ounces
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
64 ± 1.645 × 5.1/√22
= 64 ± 1.645 × 1.087
= 64 ± 1.788
The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces
The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces
Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces
Answer:
x=6
Step-by-step explanation:
When you have 7x+5=5x+17, you try to get the variables on one side and the constants on the other. Subtract 5x from the right and from the left: 2x+5=17. Next, subtract 5 from the left and from the right: 2x=12. The last step is to get rid of the coefficient of x and to do that divide it by the coefficient(in this case divide both sides by 2). After dividing 2x and 12 by 2 you get x=6.
Answer:
0.5
Step-by-step explanation:
