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hammer [34]
4 years ago
6

10 points Why does fusion stop in the star's core once it reaches iron?

Physics
2 answers:
Lina20 [59]4 years ago
5 0
Because there’s too much heat
MaRussiya [10]4 years ago
4 0
There’s too much heat that’s why
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Work out the efficiency of a lamp that transfers 7500 kJ of energy, 4500 kJ of which is transferred into light energy, 2900 kJ o
aev [14]
I think the answer is 0.4
so 40%

hope this helps :)
8 0
3 years ago
Use of a buffered temperature probe is the most accurate way to measure actual vaccine temperatures.
Marianna [84]

The most precise method for determining the actual temperature of vaccines is to use a buffered temperature probe.

<h3>What is temperature?</h3>

Temperature directs to the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity.

Temperature is essential in all areas of Science right from Physics to Geology and also it is important in most parts of our everyday life.

The complete question is;

"What type of device should be used for measuring temperatures in a vaccine storage unit?"

A temperature monitoring system is required in every vaccine storage facility.

A buffered temperature probe offers the most precise storage unit temperature information, including a thorough history of how long a unit has been running beyond the advised temperature range.

Hence, the use of a buffered temperature probe is the most accurate way to measure actual vaccine temperatures.

To learn more about the temperature refer to the link;

brainly.com/question/7510619

#SPJ1

7 0
2 years ago
A series circuit has a capacitor of 10−5 F, a resistor of 3 × 102 Ω, and an inductor of 0.2 H. The initial charge on the capacit
Alexus [3.1K]

Given the values to proceed to solve the exercise, we resort to the solution of the exercise through differential equations.

The problem can be modeled through a linear equation, in the form:

10^5 Q +300Q'+0.2Q''=0

With the initial conditions as,

Q(0) = 10^{-6}

Q'(0)= 0

Where Q(t) is the charge.

<em>The general solution of a linear equation is given as:</em>

<em>y(x) = c_1e^{-ax}+c_2e^{-bx}</em>

Applying this definiton in our differential equation we have that

Q(t) = C_1e^{at}+C_2e^{bt}

To find b and a we use the first equation and find the roots:

r_{a,b} = \frac{-300 \pm \sqrt{(300)^3-4(0.2)*10^5}}{0.4}

r_{a,b} = {-1000,-500}

Then we have

Q(t) = C_1e^{-1000t}+C_2e^{-500t}

To find the values of the Constant we apply the initial conditions, then

Q(0)= 10^{-6} = C_1+C_2

And for the derivate:

Q'(t) = -1000C_1e^{-1000t}-500C_2e^{-500t}

0 = -1000C_1e^{-1000(0)}-500C_2e^{-500(0)}

0 = -1000C_1-500C_2

We have a system of 2x2:

(1) 10^{-6} = C_1+C_2

(2) 0 = -1000C_1-500C_2

Solving we have:

C_1 = -10^{-6}

C_2 = 2*10^{-6}

The we can replace at the equation and we have that the Charge at any moment is given by,

Q(t) = (-10^{-6})e^{-1000t}+( 2*10^{-6})e^{-500t}

If we obtain the derivate we find also the Current, then

I(t)= 10^{-3}e^{-1000t}-10^{-3}e^{-500t}

7 0
3 years ago
What is the bump on the lateral side just proximal to the 5th metatarsal?
xeze [42]
The description refers to the styloid process or tuberosity. This styloid process is seen in the 5th metatarsal and this area shows the fifth metatarsal's growth plate. This bone is being attached by strong tendon known as the <span>Peroneus brevis tendon.</span>
6 0
4 years ago
A ball is tossed with a velocity of 10 m/s directed vertically upward from a window located 20 m above the ground. Determine the
marusya05 [52]

Answer:

Explanation:

Given

Initial velocity of ball u=10\ m/s

height of window h=20\ m

Using Equation of motion

y=ut+\frac{1}{2}at^2

where u=initial velocity

t=time

a=acceleration

As ball is already is at a height of 20 m so

Y=ut+\frac{1}{2}at^2+20

Y=10\times t+0.5\times (-9.8)t^2+20

Y=-4.9t^2+10t+20

(b)highest point is obtained at v=0

v^2-u^2=2as

where

v=final velocity

u=initial velocity

a=acceleration

s=displacement

(0)-10^2=2\times (-9.8)\times s

s=\frac{100}{19.6}

s=5.102\ m

Highest Point will be s+20=25.102\ m

(c)Time taken when the ball hit the ground i.e. at Y=0

-4.9t^2+10t+20=0

t=3.28\ s

impact velocity v=\sqrt{2\times 9.8\times 25.102}

v=22.181\ m/s

7 0
3 years ago
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