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dsp73
3 years ago
15

What happens when magma rises towards the surface?

Physics
2 answers:
mote1985 [20]3 years ago
7 0
Magma is an intensely hot region deep within the Earth that rises<span> to just underneath the </span>surface<span>. Some hot spots produce volcanoes. rock formed by the cooling of </span>magma<span> or lava. molten rock, or </span>magma, that erupts from volcanoes or fissures in the Earth's <span>surface</span>
zzz [600]3 years ago
5 0
It slowly cools an hardens,eventually turning into igneous rock<span />
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Which pair of terms correctly fills the blanks in the following sentence? ________ is a property of an object while ________ is
Murljashka [212]

Answer:

D) resistance, resistivity

Explanation:

Resistance is a physical quantity that indicates the opposition of an object to conduct electricity, this quantity depends on different factors such as temperature, material, object length, among other things. The resistance of two objects of the same material may be different, because it depends on the specifications of the object.

On the other hand, resistivity is a more general quantity, since it is assigned to materials and depends only on the nature of the material and its temperature.

So the resistivity is related to the meterial rather than the object.

The answer is: Resistance is a property of an object while resistivity is a property of a material.

8 0
3 years ago
What does it mean when the orbital eccentricity of a planet is close to 1?
ankoles [38]

We have that Zero signifies a perfect circle shape and 1 shows it maximum out of order shape.

From the question we are told

What does it mean when the orbital eccentricity of a planet is close to 1

Generally

Eccentricity

This in its simplest definition means to be eccentric which means to be a bit out of order or for the given subject at hand means to be a bit out of shape

Naturally the Eccentricity that an object possess is defined by two number 0(zero) to 1(one)

Where

Zero signifies a perfect circle shape and 1 shows it maximum out of order shape

For more information on this visit

brainly.com/question/17208989?referrer=searchResults

7 0
2 years ago
Read 2 more answers
Two charges, one of 2.50μC and the other of -3.50μC, are placed on the x-axis, one at the origin and the other at x = 0.600 m
aev [14]

Answer:

Explanation:

Given

charge of first body q_1=2.5\ mu C

charge of second body q_2=-3.5\ mu C

Particle 1 is at origin and particle 2 is at x=0.6\ m

third Particle which charge +q must be placed left of 2.5\mu C because it will repel the q charge while -3.5\mu C will attract it

suppose it is placed at a distance of x m

F_{1q}=\frac{kq(2.5)}{x^2}

F_{2q}=\frac{kq(-3.5)}{(0.6+x)^2}

F_{1q}+F_{2q}=0

\frac{kq(2.5)}{x^2}+\frac{kq(-3.5)}{(0.6+x)^2}=0

\frac{kq(2.5)}{x^2}=\frac{kq(3.5)}{(0.6+x)^2}

\frac{0.6+x}{x}=(\frac{3.5}{2.5})^{0.5}

0.6+x=1.1832x

x=3.27\ m

5 0
3 years ago
Linearly polarized light whose Jones vector is [0 1] (horizontally polarized) is sent through a train of two linear polarizers.
ivann1987 [24]

Answer:

Following are the solution to the given question:

Explanation:

The input linear polarisation was shown at an angle of 2 \mu. It's a very popular use of a half-wave plate. In particular, consider the case \mu = 45 \pm, at which the angle of rotation is 90\pm. HWP thereby provides a great way to turn, for instance, a linear polarised light that swings horizontally to polarise vertically. Illustration of action on event circularly polarized light of the half-wave platform. Customarily it is the slow axis of HWP that corresponds to either the rotation. Note that perhaps the vector of polarization is "double-headed," i.e., the electromagnetic current swinging back and forward in time. Therefore the turning angle could be referred to as the rapid axis to reach the same result. Please find the attached file.

8 0
2 years ago
A ball of mass m on a string of length L is attached to a pivot. The ball is released from rest while the string is parallel to
mash [69]

Answer:

L/2

Explanation:

Neglect any air or other resistant, for the ball can wrap its string around the bar, it must rotate a full circle around the bar. This means the ball should be able to swing to the top position where it's directly above the bar. By the law of energy conservation, this happens when the ball is at the same level as where it's previously released vertically. It means the swinging radius around the bar must be at least half of the string length.

So the distance d between the bar and the pivot should be at least L/2

8 0
3 years ago
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