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dsp73
3 years ago
15

What happens when magma rises towards the surface?

Physics
2 answers:
mote1985 [20]3 years ago
7 0
Magma is an intensely hot region deep within the Earth that rises<span> to just underneath the </span>surface<span>. Some hot spots produce volcanoes. rock formed by the cooling of </span>magma<span> or lava. molten rock, or </span>magma, that erupts from volcanoes or fissures in the Earth's <span>surface</span>
zzz [600]3 years ago
5 0
It slowly cools an hardens,eventually turning into igneous rock<span />
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3 years ago
A power company charges its customers for electricity based upon which one of the following?a. powerb. energyc. power per unit o
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B. Energy

A power company charges its customers for electricity based upon B. Energy.

<h3>Explanation:</h3>

Kilo-watt Hours (kWh) is the unit that measures the electricity consumption of customers. Since Power is defined as the rate at which electrical energy is transferred by an electrical circuit per unit time,

P = \frac{E}{t} \\E= P\times t

If energy is transmitted at a constant rate over a period of time, the total energy in kilowatt hours is the product of power in kilowatts(kW) and time in hours (h)

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3 years ago
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Liono4ka [1.6K]
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4 0
3 years ago
Read 2 more answers
A transparent oil with index of refraction 1.28 spills on the surface of water (index of refraction 1.33), producing a maximum o
Veseljchak [2.6K]

To solve this problem we will apply the concepts related to the principle of destructive and constructive interference. Mathematically this expression can be given as

2nt = m\lambda

Here,

n = Index of refraction

t = Thickness

m = Order of the reflection

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3 0
3 years ago
A 12.5843-gram sample of metal bromide, MBr4, was dissolved and, after reaction with silver nitrate, AgNO3, all of the bromide w
barxatty [35]

Answer:

zirconium

Explanation:

Given, Mass of AgBr(s) = 23.0052 g

Molar mass of AgBr(s) = 187.77 g/mol

The formula for the calculation of moles is shown below:

Moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles\ of\ AgBr= \frac{23.0052\ g}{187.77\ g/mol}

Moles\ of\ AgBr= 0.1225\ mol

The reaction taking place is:

MBr_4+4AgNO_3\rightarrow 4AgBr+M(NO_3)__4

From the reaction,

4 moles of AgBr is produced when 1 mole of MBr_4 undergoes reaction

1 mole of AgBr is produced when 1 / 4 mole of MBr_4 undergoes reaction

0.1225 mole of AgBr is produced when \frac {1}{4}\times 0.1225 mole of MBr_4 undergoes reaction

Moles of MBr_4 got reacted = 0.030625 moles

Mass of the sample taken = 12.5843 g

Let the molar mass of the metal = x g/mol

So, Molar mass of MBr_4 = x + 4 × 79.904 g/mol = 319.616 + x g/mol

Thus,

0.030625 = \frac{12.5843}{319.616 + x}

Solve for x,

we get, x = 91.2999 g/mol

<u>The metal shows +4 oxidation state and has mass of 91.2999 g/mol . The metals is zirconium.</u>

8 0
3 years ago
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