An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
1 answer:
Answer:
675m
Explanation:
Given parameters:
Initial velocity = 0m/s
Acceleration = 6m/s²
Time = 15s
Unknown:
Distance traveled by the body = ?
Solution:
To solve this problem; we use the expression;
S = ut + at²
Where u is the initial velocity
t is the time
a is the temperature
Insert the parameters and solve;
S = 0 x 15 + x 6 x 15²
S = 675m
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Answer:
21.48 km 2.92° north of east
Explanation:
To find the resultant direction, we need to calculate a sum of vectors.
The first vector has module = 13 and angle = 315° (south = 270° and east = 360°, so southeast = (360+270)/2 = 315°)
The second vector has module 16 and angle = 40°
Now we need to decompose both vectors in their horizontal and vertical component:
horizontal component of first vector: 13 * cos(315) = 9.1924
vertical component of first vector: 13 * sin(315) = -9.1924
horizontal component of second vector: 16 * cos(40) = 12.2567
vertical component of second vector: 16 * sin(40) = 10.2846
Now we need to sum the horizontal components and the vertical components:
horizontal component of resultant vector: 9.1924 + 12.2567 = 21.4491
vertical component of resultant vector: -9.1924 + 10.2846 = 1.0922
Going back to the polar form, we have:
So the resultant direction is 21.48 km 2.92° north of east.
Answer:
The answer is "151.25 J and -547.64 J".
Explanation:
Using formula:
Calculating the Work by net force
The above work is converted into thermal energy.
Now,