All categories

3 years ago

Which method can be used to prove that AJKL is congruent to AJML? SSS OHL SAS ASA

Mathematics

2 answers:

IrinaK [193]3 years ago

8 0

Answer:

it is SAS

Step-by-step explanation:

side angle side

triangle JKL is congruent to triangle JML

because they have two equal sides:

JL whitch is common in both of them and ML equal to KL

and the included angles are equal.

jeka57 [31]3 years ago

5 0

Answer:

I think the answer is SAS(side angle side).

Step-by-step explanation:

HOPE THIS HELPS YOU!!

PLEASE MARK ME AS BRAINLIEST!!!

You might be interested in

How many 1-inch cubes do you need to fill a cube that has an edge length of 1 foot?

givi [52]

12^3 = 1728 cubes needed.
Since it is volume, and there are 12 inches in one foot, 12 inches will be cubed (to the third power) which gives a total of 1728 cubes needed to fill the cube.

4 0

3 years ago

Read 2 more answers

Can anyone help with this?

lapo4ka [179]

Answer:

figure it out yourself

Step-by-step explanation:

remember, all three of the triangle's interior angles should add up to 180 degrees.

6 0

3 years ago

Read 2 more answers

(Grade7geomtery) Can somebody plz help answer these questions correctly (only if u know how to do this) thx sm! :3

ArbitrLikvidat [17]

Answer:

<1 = 47

<2 = 65

<3 =68

<4 = 68

Step-by-step explanation:

3 0

3 years ago

For the figure shown on the right, find the value of the variable and the measures of the angles.

Mashutka [201]

Answer:

angle R = 37

angle Q= 114

angle p = 29

Step-by-step explanation:

(3x+3) +(x-8) +(x) =180

5x-5=180

x=185/5

x=37

4 0

3 years ago

Students attending the University of Florida can select from 130 major areas of study. A student's major is identified in the re

omeli [17]

Answer:

1. 8385 double majors

2. 18252 major codes

3. 8515 codes

4. Yes

Step-by-step explanation:

Given

Major areas = 130

Alphabets = 26

There are 130 major areas in the university.

To get a double majors, means one select any of two of the major areas in the university.

i.e. just 2 alphabets are needed

Number of Double Majors = 130C2

130C2 = 130!/(128!*2!)

130C2 = 130 * 129/2

130C2 = 8385.

Number of major codes available = Number of 2 digit codes + Number of 3 digit codes

Number of 2 digit codes = 2 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

So, number of 2 digit codes = 26 * 26 = 676.

Number of 3 digit codes = 3 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

There are 26 ways of selecting the third letter

So, number of 3 digit codes = 26 * 26 * 26 = 17576

Thus, number of major codes = 17576 + 676 = 18252

Number of codes to identify a student with either a single major or double major

Number off single major codes = number of major areas = 130

Number of double major codes = 8385

Total = 130 + 8385 = 8515

d. From the solutions above, Yes there are enough codes available to identify all single and double majors at the university

6 0

3 years ago