All categories

4 years ago

What is the gradient of a curve going through points (1,5) and (6,35)?

Mathematics

2 answers:

ozzi4 years ago

7 0

Answer:

Step-by-step explanation:

Gradient = (y2-y1)/(x2-x1)

= (35-5)/(6-1)

= 30/5

= 6

FinnZ [79.3K]4 years ago

3 0

Answer:

Step-by-step explanation:

The gradient is simply the change in y divided by the change in x.

Change in y is the difference in y-coordinates, while the change in x is the difference in x-coordinates. Our two points here are (1, 5) and (6, 35).

The difference in y-coordinates is: 35 - 5 = 30. The difference in x-coordinates is: 6 - 1 = 5. Divide 30 by 5:

30 / 5 = 6

Thus, the gradient is 5.

You might be interested in

What is the solution of 3p+2≥−10

sladkih [1.3K]

Answer:

the solution os 3p+2≥-10 is p≥-4

Step-by-step explanation:

So.... 3p+2≥-10

3p≥-12

and then you divide...... 3p≥-12

p≥-4

3 0

3 years ago

The original price p of an item less a discount of 15%

Snowcat [4.5K]

P-.15p this is the expression for cost after discount

and its just .15p for just the discount

7 0

3 years ago

Read 2 more answers

The graph below shows the number of dimes and nickels in a child’s piggy bank.

kirill115 [55]

Answer:

60 dimes 35 nickels

Step-by-step explanation:

6 0

3 years ago

Find the derivatives of the following implicit function

ddd [48]

Answer:

$\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

Step-by-step explanation:

$3x^2-6xy+y^2=2x-y\\\mathrm{Treat\:}y\mathrm{\:as\:}y\left(x\right)\\\mathrm{Differentiate\:both\:sides\:of\:the\:equation\:with\:respect\:to\:}x\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=\frac{d}{dx}\left(2x-y\right)\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(2x-y\right)=2-\frac{d}{dx}\left(y\right)\\6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)=2-\frac{d}{dx}\left(y\right)$

$\mathrm{For\:convenience,\:write\:}\frac{d}{dx}\left(y\right)\mathrm{\:as\:}y^{'\:}\\6x-6\left(y+xy^{'\:}\right)+2yy^{'\:}=2-y^{'\:}\\\mathrm{Isolate}\:y^{'\:}:\quad y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\\mathrm{Write}\:y^{'\:}\:\mathrm{as}\:\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

3 0

3 years ago

Explain how to write 3 X3/8 as the product of a whole number and a unit fraction

mars1129 [50]

A unit fraction means that the fraction has 1 in the numerator. To make 3/8 a unit fraction, you have to make it 1/8 by dividing by 3.

So now you have 3 x 3 x 1/8. You can multiply the 3 and 3.

You are left with 9 x 1/8.

6 0

3 years ago