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pav-90 [236]
3 years ago
7

Anyone??

Mathematics
1 answer:
Kipish [7]3 years ago
7 0
The answer should be  596 because the difference between the months is 7. So if u multiply 7*17 you would get 119
. So then u subtract 119 from 715 giving you your answer of
596
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If the cost of 1 packet biscuit is Rs.17.50,what is the cost of 8 packets of biscuits?​
disa [49]
1 paket bisküvinin maliyeti Rs. 17.50 ise, 8 paket bisküvinin maliyeti nedir?
5 0
3 years ago
The original amount owed on a loan is known as
beks73 [17]

Answer:

The original amount owned on a loan is known as principal.

7 0
3 years ago
Someone please explain number four thanks
devlian [24]
1/5 of 3 ..
=> 1/5 * 3 is same as 3 * 1/5 ..
=> 1/5*3 = 3/5 and 3* 1/5 also = 3/5 ...
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8 0
3 years ago
A roof has the shape of an isosceles triangle with equal sides 8 cm long and base 12 m long. What is the measure of the angle of
victus00 [196]

Answer:

41 degrees to the nearest degree.

Step-by-step explanation:

A line drawn from the vertex and bisecting the base forms 2 right triangles.

The base of one right triangle = 1/2 * 12 = 6 m.

So cos A = adjacent side /hypotenuse   where A is the angle of inclination.

cos A=  6 / 8 = 0.75

m < A = 41.41 degrees.

7 0
3 years ago
The population standard deviation for the typing speeds for secretaries is 4 words per minute. If we want to be 90% confident th
Oksana_A [137]

Answer:

The minimum sample size that should be taken is 62.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

If we want to be 90% confident that the sample mean is within 1 word per minute of the true population mean, what is the minimum sample size that should be taken

This is n when M = 1, \sigma = 4. So

M = z*\frac{\sigma}{\sqrt{n}}

1 = 1.96*\frac{4}{\sqrt{n}}

\sqrt{n} = 4*1.96

(\sqrt{n})^{2} = (4*1.96)^{2}

n = 61.5

The minimum sample size that should be taken is 62.

8 0
3 years ago
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