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KatRina [158]
3 years ago
8

Factor this expression completely, then place the factors in the proper location on the grid. 5x3 + 40y6

Mathematics
2 answers:
Molodets [167]3 years ago
6 0
For this case we have the following expression:
 5x3 + 40y6
 Common factor 5:
 5 (x3 + 8y6)
 Factoring the expression within the parenthesis we have:
 5 ((x + 2y2) (x2 - 2xy2 + 4y4))
 Answer:
 
The factored expression is given by:
 
5 ((x + 2y2) (x2 - 2xy2 + 4y4))
Daniel [21]3 years ago
3 0

Answer: The expression after completely factorised form is

5[(x+2y^2)(x^2+4y^4-2xy^2)]

Step-by-step explanation:

Since we have given that

5x^3 + 40y^6

We need to factorise it completely:

5x^3 + 40y^6\\\\=5(x^3+8y^6)\\\\=5((x)^3+(2y^2)^3)\\\\=5[(x+2y^2)(x^2+4y^4-2xy^2)]\ (\because\ a^3+b^3=(a+b)(a^2+b^2-ab))

Hence, the expression after completely factorised form is

5[(x+2y^2)(x^2+4y^4-2xy^2)]

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Fraction is equivalent to a terminating decimal
11111nata11111 [884]
The best way to compare fractions would be to make them have like denominators.  We first , in this case, need to convert from decimal to fraction. 

                 Converting decimals to fractions first requires an understanding of the decimal places that fall after the decimal.  One place after the decimal is the tenths place.  If you have a decimal that ends at one place after the decimal (or in the tenths place) it can be written as the number after the decimal in the top of the fraction and ten (tenths place) in the denominator.  ex.   .5 ends one place after the decimal and can be written as 5/10...(read as five tenths).

If a decimal ends at two places after the decimal...(ex.   .75)...it ends in the hundredths place, can be written as that number in the numerator and 100 in the denominator....(ex  75/100) and is read as seventy-five hundredths. 

one place after the decimal is tenths (over 10), two places is hundredths (over 100), three places is thousandths (over 1000) , four places ten-thousandths (over 10000) and so on.

Because each decimal in your problem has a different amount of decimal places, it makes for different denominators. But, We can add a zero to the end of a decimal without changing it's value; if we add a zero to the end of .5 and make it .50 , we then can write it as 50/100 and would now have like denominators.

if .5 = .50 = 50/100 and .75 = 75/100

we now have the question what fractions can fall between 50/100 and 75/100. 

That would be fractions such as 51/100, 52/100, 53/100.......74/100.


6 0
3 years ago
Jen walked 1/4 of a mile in 1/2 of an hour. At this rate, how long will it take her to walk 2 miles to the park?
Leto [7]

Answer:

The awnser is C. 4 hours

Step-by-step explanation:

It takes her 2 hours two walk 1 mile so 2*2 is 4

4 0
3 years ago
FIND X AND Y. GIVING BRAINLIEST AND 100 POINTS
aksik [14]

Answer:

here u can look

Mark as brainlist

Step-by-step explanation:

X + y = 120(being alternate angle)

or,X=120-y

then

2x-y=120

or,2(120-y) - y= 120

240-2y-y=120

y=240-120

y= 120

again,

X=120-y

= 120-120

=0

hence,

X= 0

y= 120

6 0
2 years ago
Read 2 more answers
PLEASE HELP<br><br>divide. (3x-2)(x-4)-(x-4)(6-5x)<br>/(4-x)(8x-1)​
8_murik_8 [283]

Answer:

x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

Step-by-step explanation:

Solve for x:

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = 0

Simplify and substitute y = 4 - x.

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = -434 + 257 (4 - x) - 37 (4 - x)^2

= -37 y^2 + 257 y - 434:

-37 y^2 + 257 y - 434 = 0

Divide both sides by -37:

y^2 - (257 y)/37 + 434/37 = 0

Subtract 434/37 from both sides:

y^2 - (257 y)/37 = -434/37

Add 66049/5476 to both sides:

y^2 - (257 y)/37 + 66049/5476 = 1817/5476

Write the left hand side as a square:

(y - 257/74)^2 = 1817/5476

Take the square root of both sides:

y - 257/74 = sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

y = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Substitute back for y = 4 - x:

4 - x = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Subtract 4 from both sides:

-x = sqrt(1817)/74 - 39/74 or y - 257/74 = -sqrt(1817)/74

Multiply both sides by -1:

x = 39/74 - sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

x = 39/74 - sqrt(1817)/74 or y = 257/74 - sqrt(1817)/74

Substitute back for y = 4 - x:

x = 39/74 - sqrt(1817)/74 or 4 - x = 257/74 - sqrt(1817)/74

Subtract 4 from both sides:

x = 39/74 - sqrt(1817)/74 or -x = -39/74 - sqrt(1817)/74

Multiply both sides by -1:

Answer:  x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

7 0
3 years ago
What is the slope of a line perpendicular to the line whose equation is x-y=6x−y=6. Fully simplify your answer.
svlad2 [7]
It should by the answer but if not sorry
Answer:
(X,Y)
(0,6)
4 0
2 years ago
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