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KatRina [158]
4 years ago
8

Factor this expression completely, then place the factors in the proper location on the grid. 5x3 + 40y6

Mathematics
2 answers:
Molodets [167]4 years ago
6 0
For this case we have the following expression:
 5x3 + 40y6
 Common factor 5:
 5 (x3 + 8y6)
 Factoring the expression within the parenthesis we have:
 5 ((x + 2y2) (x2 - 2xy2 + 4y4))
 Answer:
 
The factored expression is given by:
 
5 ((x + 2y2) (x2 - 2xy2 + 4y4))
Daniel [21]4 years ago
3 0

Answer: The expression after completely factorised form is

5[(x+2y^2)(x^2+4y^4-2xy^2)]

Step-by-step explanation:

Since we have given that

5x^3 + 40y^6

We need to factorise it completely:

5x^3 + 40y^6\\\\=5(x^3+8y^6)\\\\=5((x)^3+(2y^2)^3)\\\\=5[(x+2y^2)(x^2+4y^4-2xy^2)]\ (\because\ a^3+b^3=(a+b)(a^2+b^2-ab))

Hence, the expression after completely factorised form is

5[(x+2y^2)(x^2+4y^4-2xy^2)]

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VARVARA [1.3K]

Answer:

y = 1.33

Step-by-step explanation:

What you could do is :

x-1x = 2y + 1x-1x + y = 4

get rid of the x

>>> 2y + y = 4

then combine the like terms or y:

2y + y

>>> 3y = 4

finally: divide 4/3

3y/3= 4/3

>>> y = 1.33

Hope it Helps!

3 0
3 years ago
PLEASE HELP!!!!!!!!!!!
Firlakuza [10]
I believe since ABD is 60, DBC is also 60 and then ABC is 120
8 0
3 years ago
Catherine has $400 in her checking account. She writes a check for $600. What is the balance of her account?
nevsk [136]

Answer:

Her new balance is $-200

$400 - $600 is $-200

8 0
3 years ago
Read 2 more answers
Express the area A of a circle as a function of its​ radius, r. Determine the area of a circle whose radius is 11 inches. That​
nekit [7.7K]
<h2>Answer with explanation:</h2>

The function represents the area of a circle(A) is given by :-

A(r)=2\pi r

To determine the area of a circle whose radius is 11 inches. , we put the value of r=11 inches, we get

A(11)=2\pi (11)

Now, we put \pi=\dfrac{22}{7} in the above function , we get

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8 0
3 years ago
What is the value of b? −7.5(x−3)=3.75 Enter your answer in the box.
choli [55]
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3 0
4 years ago
Read 2 more answers
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