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KatRina [158]
3 years ago
8

Factor this expression completely, then place the factors in the proper location on the grid. 5x3 + 40y6

Mathematics
2 answers:
Molodets [167]3 years ago
6 0
For this case we have the following expression:
 5x3 + 40y6
 Common factor 5:
 5 (x3 + 8y6)
 Factoring the expression within the parenthesis we have:
 5 ((x + 2y2) (x2 - 2xy2 + 4y4))
 Answer:
 
The factored expression is given by:
 
5 ((x + 2y2) (x2 - 2xy2 + 4y4))
Daniel [21]3 years ago
3 0

Answer: The expression after completely factorised form is

5[(x+2y^2)(x^2+4y^4-2xy^2)]

Step-by-step explanation:

Since we have given that

5x^3 + 40y^6

We need to factorise it completely:

5x^3 + 40y^6\\\\=5(x^3+8y^6)\\\\=5((x)^3+(2y^2)^3)\\\\=5[(x+2y^2)(x^2+4y^4-2xy^2)]\ (\because\ a^3+b^3=(a+b)(a^2+b^2-ab))

Hence, the expression after completely factorised form is

5[(x+2y^2)(x^2+4y^4-2xy^2)]

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Point P lies on the line with the equation y-4=3(x-2). If the x-coordinate of P is 4, what is the y-coordinate of P
maw [93]
Let's start by tidying up that equation and put it into slope-intercept form (y = mx + b); from there, we can plug in coordinates.

y - 4 = 3(x-2)

Let's use the distributive property on the right side:
y - 4= 3x - 6

Now add 4 to both sides
(y - 4) + 4 = (3x - 6) + 4

Which simplifies to:
y = 3x - 2

Since that's the equation of our line, now we can plug in coordinates and see what it churns out. 

We know that the x-coordinate of P = 4 so let's substitute 4 in for x and calculate the y-coordinate:

y = 3(4) - 2
y = 12 - 2
y = 10

So the y-coordinate for point P = 10
6 0
3 years ago
Please look at this question, thanks
Oxana [17]

Answer:

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Ierofanga [76]
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Please help with all parts (ignore my answer for the first one)
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Please edit your question to what is the question
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