Question

A 0.50-mm-wide slit is illuminated by light of wavelength 500 nm. What is the width of the central maximum on a screen 2.0 m behind the slit?

Answer 1

Answer:

$w=4*10^{-3}m\\or\\w=4mm$

Explanation:

A single slit of width x has bright central maximum of width:

ω=(2λL)/x

Given data

x=0.50 mm

λ(wavelength)=500 nm

L(length)=2.0 m

Substitute the given values to find width w

So

$w=\frac{2*(500*10^{-9}m )(2.0m)}{(0.5*10^{-3})}\\w=4*10^{-3}m\\or\\w=4mm$