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Afina-wow [57]
4 years ago
10

Extra credit calculate the total mechanical energy of a pendulum as it swings from its highest point to its lowest point

Physics
1 answer:
Korolek [52]4 years ago
4 0
Is there any numbers to your question?
Keep in mind, the energy is conserved in a pendulum.
Here’s more information:
https://blogs.bu.edu/ggarber/interlace/pendulum/energy-in-a-pendulum/
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Answer:

B. Decrease the plane’s speed and height

Explanation:

Decrease in speed of plane:

When the speed of the plane is decreased then initial velocity of the package will be lesser. As a result, final velocity will also be lesser because in this case final velocity depends upon the initial velocity.

Decrease in height:

According to law of conservation of energy:

Loss in potential energy = Gain in Kinetic energy  

                                 mgh = ½ mV^2

It means with the decrease in height less potential energy will be converted to kinetic energy. As package has constant mass so it will gain less velocity.

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How do you call a number of waves that pass a given point in a specific time, commonly one second.
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That's the "frequency" of the wave.
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3 years ago
7. How fast is Michael accelerating if his mass is 10 kg and he is exerting
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150 m/s²

Explanation:

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Please help me on due today
Bad White [126]

Subject-Matter Achievement Goal

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Answer: a planner so I can pace myself

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15. My personal enrichment goal is:

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16. My action steps are:

Answer: eat healthier foods

17. My time frame is:

Answer: now to the end of the school year

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4 0
3 years ago
A warm hockey puck has a coefficient of restitution of 0.50, while a frozen hockey puck has a coefficient of restitution of only
AlexFokin [52]

Answer:

the required height is 0.2449 m only

Explanation:

Given the data in the question;

Initial height = 2m

so speed of the puck before hitting the ground will be;

u² = 2gh

Initial speed u_ball = √2gh

u_ball = √( 2 × 9.8 × 2 )

u_ball =  √39.2

u_ball = 6.26 m/s

given that; FOR THE FROZEN PUCK, coefficient of restitution = 0.35 only

R = - (v_ball - v_ground / u_ball - u_ ground)

so

0.35 = - (v_ball - 0 / 6.26 - 0)

0.35 = -v_ball / - 6.26

-v_ball = 0.35 × (- 6.26)

-v_ball = -2.191 m/s

v_ball = 2.191 m/s

to get the height;

v² = 2gh

h = v² / 2g

we substitute

h = (2.191)² / 2×9.8

h = 4.800481 / 19.6

h = 0.2449 m

Therefore, the required height is 0.2449 m only

5 0
3 years ago
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