Question

An object is placed a distance of 50 cm from a convex mirror of radius 40 cm. What is the magnification? O 3.5 O 2.5 O 0.3 0.5

Answer 1

Explanation:

Given that,

Object distance, u = -50 cm

Radius of curvature of the convex mirror, R = 40 cm

Focal length of the convex mirror, $f=\dfrac{R}{2}=20\ cm$

We need to find the magnification of the mirror. Firstly, it is required to find the image distance using formula as:

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

$\dfrac{1}{f}-\dfrac{1}{u}=\dfrac{1}{v}$

$\dfrac{1}{20}-\dfrac{1}{-50}=\dfrac{1}{v}$

v = 14.28 cm

Magnification of the mirror,

$m=\dfrac{-v}{u}$

$m=\dfrac{-14.28}{-50}$

m = 0.28

So, the magnification of the mirror is 0.28.Hence, this is the required solution.