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Eddi Din [679]
4 years ago
9

A farmer raises cows and chickens. There are a total of 114 legs and 42 animals 4y = cow legs and 2x = chicken legs. how many co

ws and chickens the farmer has
Mathematics
2 answers:
Fofino [41]4 years ago
4 0
X+y=42, 4y+2x=114

y=42-x

4(42-x)+2x=114
168-4x+2x=114
168-2x=114
168-114=2x
54=2x
54/2=x
27=x

plug 27 into y=42-x

y=42-27
y=15
fgiga [73]4 years ago
4 0
Use algebraic formula:
(Animal Type 1:X)x(Number of Legs on that type) + (Animal Type 2:Y)x(Number of Legs on that type) = Total number of legs

2x+4y = 114
Also: X+Y = 42
Divide he equation 2x+4y=114 by 2 on both sides = x+2y=57
If X+Y = 42, and x+2y=57 then Y must = 15 (subtract X+Y from one side and 42 from the other)
15 cows 27 chickens = 114 legs 42 heads

This formula works regardless of how many ‘legs’ the creature type has. Just plug in the appropriate value in the original equation to match the new criteria.
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ohaa [14]
112(1/8)

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answer is 14.
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[need math help] Study buddies part #2
rosijanka [135]

Answer:

Part A) The distance between Whitney's house and Anh's house is 6.5 miles.

Part B) The total distance traveled by Whitney during the trip was 9.5 miles.

Step-by-step explanation:

Part A)

Notice that during Whitney's journey to Anh's house, her velocity was negative for some time. So, Whitney was travelling backwards. Hence, the total distance Whitney traveled will be greater than the actual distance from Whitney's house to Anh's.

So, instead, we can calculate Whitney's total displacement. Total displacement is given by:

\displaystyle \text{Displacement}=\int_a^bv(t)\, dt

Where <em>v(t)</em> is the velocity function.

So, the displacement of Whitney when she traveled from her house to Anh's house will be:

\displaystyle \text{Displacement}=\int_0^{24}v(t)\, dt

To calculate the integral, we can split it off at <em>t</em> = 11, <em>t</em> = 16, and <em>t</em> = 24.

The three regions represent three geometric figures, which we can use to calculate the area and then find the integral. Rewriting:

\displaystyle \text{Displacement}=\int_0^{11}v(t)\, dt+\int_{11}^{16}v(t)\, dt+\int_{16}^{24}v(t)\, dt

Now, we can calculate the area of each figure.

The first figure is a trapezoid with a height of 0.8 and two bases of 11 and 3. So, its area is:

\displaystyle A_1=\frac{1}{2}(0.8)(11+3)=5.6\text{ miles}

The second figure is a triangle with a height of 0.6 and a base of 5. So, its area is:

\displaystyle A_2=\frac{1}{2}(0.6)(5)=1.5\text{ miles}

Lastly, the third figure is another triangle will a height of 0.6 and a base of 8. So, its area is:

\displaystyle A_3=\frac{1}{2}(0.6)(8)=2.4\text{ miles}

However, notice that the second figure is below the <em>x</em>-axis. During that interval, Whitney was traveling backwards. Hence, we will subtract the second area from the rest of the areas.

Then the displacement will be:

\displaystyle \text{Displacement}=5.6-1.5+2.4=6.5\text{ miles}

So, the distance between Whitney's house and Anh's house is 6.5 miles.

Part B)

The total distance differs from displacement in that it includes all the distances in both directions. It is given by:

\displaystyle \text{Distance}=\int_a^b|v(t)|\, dt

In other words, all of our values are now positive. We will utilize the same strategy:

\displaystyle \text{Distance}=\int_0^{11}|v(t)|\, dt+\int_{11}^{16}|v(t)|\, dt+\int_{16}^{24}|v(t)|\, dt

Substitute. The only difference is that we will add 1.5 instead of subtracting it. So:

\displaystyle \text{Distance} =5.6+1.5+2.4=9.5

Therefore, in this instance, Whitney traveled a total of 9.5 miles to get to Anh's house.

6 0
3 years ago
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