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Eddi Din [679]
3 years ago
9

A farmer raises cows and chickens. There are a total of 114 legs and 42 animals 4y = cow legs and 2x = chicken legs. how many co

ws and chickens the farmer has
Mathematics
2 answers:
Fofino [41]3 years ago
4 0
X+y=42, 4y+2x=114

y=42-x

4(42-x)+2x=114
168-4x+2x=114
168-2x=114
168-114=2x
54=2x
54/2=x
27=x

plug 27 into y=42-x

y=42-27
y=15
fgiga [73]3 years ago
4 0
Use algebraic formula:
(Animal Type 1:X)x(Number of Legs on that type) + (Animal Type 2:Y)x(Number of Legs on that type) = Total number of legs

2x+4y = 114
Also: X+Y = 42
Divide he equation 2x+4y=114 by 2 on both sides = x+2y=57
If X+Y = 42, and x+2y=57 then Y must = 15 (subtract X+Y from one side and 42 from the other)
15 cows 27 chickens = 114 legs 42 heads

This formula works regardless of how many ‘legs’ the creature type has. Just plug in the appropriate value in the original equation to match the new criteria.
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Answer:

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Step-by-step explanation:

The question is not complete. The complete question should be in the form:

Victor has 2 fraction models. Each is divided into equal sized sections the models are shaded to represent the same fraction. Model A is divided into 6 sections and 3 sections are shaded. Model B is divided into 12 sections. What do you know about the number of sections shaded in Model B? Explain your answer.

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