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3 years ago

What is the greatest negative integer?

2 answers:

8 0

The answer is -1. A negative integer is an integer to the left of zero on the number line. It is less than 0. So the greatest negative integer is -1.

antoniya [11.8K]3 years ago

5 0

The answer is -1. Anything to the left of the number line is smaller for example -2 is smaller than -1 and after, would be 0 which is not a negative integer.

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Select all the equations on which the point (10,0) lies.

Makovka662 [10]

Answer:

B, C

Step-by-step explanation:

Since y=0, you are looking for equations such that 10 times the coefficient of x is the constant in the equation.

a) 5·10 ≠ 15

b) 2·10 = 20 . . . . select this one

c) 10 = 10 . . . . select this one

d) 3·10 ≠ 13

e) 4·10 ≠ 20

f) 6·10 ≠ 50

8 0

2 years ago

Estimate to 920,026-535,722

Sonja [21]

900000000000 i would think because 5 above is round up 4 and below round down

4 0

2 years ago

Read 2 more answers

Graph the image of this figure after a dilation with a scale factor of 2 centered at the origin.

den301095 [7]

Answer:

Here, the coordinates of the given rectangle are (1,2), (3,2), (1,-1) and (3,-1)

In the dilation by the scale factor k with centered at origin,

$(x,y)\rightarrow (kx,ky)$

Thus, If the dilation occurs by the scale factor of 2 with centered at origin,

New coordinates of the Rectangle are,

$(1,2)\rightarrow (2\times 1, 2\times 2)$

$(3,2)\rightarrow (2\times 3, 2\times 2)$

$(1,-1)\rightarrow (2\times 1, 2\times -1)$

$(3,-1)\rightarrow (2\times 3, 2\times -1)$

Thus, the coordinates of new rectangle are,

(2,4), (6,4), (2,-2) and (6,-2)

3 0

3 years ago

Read 2 more answers

Is 6/5 greater than 2/3

Natasha2012 [34]

Answer:

yes 6/5 is greater

Problem solving:

first you need to simply the fractions and see which one is bigger.

2/3 = 0.667

6/5 = 1.2

-Sumin <3

6 0

2 years ago

Read 2 more answers

Solve graphically the inequality \[ x ≥ 2 \]

Xelga [282]

1) Graph the corresponding equation $ x = 2 $; this will split the plane into two regions. One of the region represents the solution set.

2) Select a point situated in any of the two regions obtained and test the inequality. If the point selected is a solution, then all the region is the solution set. If the selected point is not a solution, then the other (second) region represents the solution set.

3) Test: In this example, let us for example select the point with coordinates (3 , 2) which is in the region to the right of the line x = 2. If you substitute x in the inequality $ x ≥ 2 $ by 3 it becomes $ 3 ≥ 2 $ which is a true statement and therefore (3 , 2) is a solution. Hence, we can conclude that the region to the right of the vertical line x = 2 is a solution set including the line itself which is shown as a solid line because of the inequality symbol $ ≥ $ contains the $ = $ symbol. The solution set is represented by the blue hash region in the graph below including the line x = 2.

6 0

3 years ago