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3 years ago

Convert 35 mi/h to km/h

1 answer:

3 0

<span>Convert 35 mi/h to km/h

</span> $35 \dfrac{mi}{h}\to \dfrac{km}{h}\qquad \qquad 1 mi= 1,60934 \\ \\ \\ 35 \dfrac{mi}{h}* \dfrac{1,60934\ km}{1\ mi}= \boxed{ 56,3269\dfrac{km}{h} }$ <span>
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What is the distance between the two coordinates points c and b?

Alecsey [184]

I believe the answer is 2 if that’s an option

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3 years ago

A circle is cut into congruent sections and arranged to form a figure that approximates a parallelogram. Find the approximate he

Solnce55 [7]

Answer:

<h2>The height is 3.43 centimeters, approximately.</h2>

Step-by-step explanation:

Notice that there are 16 pieces from the circle, which means each sector has an angle of

$\theta = \frac{360\°}{16}=22.5\°$

Where all sectors have equal area.

Now, the area of the whole circle is $12.25 \pi \ cm^{2}$ , if we use the formula of its area, we'll find the radius of the circle

$A= \pi r^{2}\\ 12.25\pi = \pi r^{2}\\ r=\sqrt{12.25} \approx 3.5$

Notice that each piece works as an isosceles triangle, because each side is the radius, that is, they have the same length. So far, we know the sides of the isosceles triangle and one internal angle.

To find the height of the one piece, we need to use trigonometric reasons, because the height divides a triangle in two equal right triangles.

$cos(11.25\°)=\frac{h}{3.5}\\ h=3.5 \times cos(11.25 \°)\\h \approx 3.43$

Therefore, the height is 3.43 centimeters, approximately.

6 0

3 years ago

nignag [31]

Answer:

1st = 4×10 ^-9

2nd= 4×10^1

3rd = 4×10^7

4th = 4×10^-5

Step-by-step explanation:

for whole numbers you just have to count from the ending till the number indicated beside the x10

for decimals you count from the front starting at the decimal till you cover the whole number

6 0

11 months ago

Communitative property of 20×72×5

Rasek [7]

The answer for this problem is 7,200

8 0

3 years ago

Read 2 more answers

I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.

masya89 [10]

Answer:

The probability mass function for the items sold is

$P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.$

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

$P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.$

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

$P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.$

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

$P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.$

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0

2 years ago