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Crank
3 years ago
12

(Would be very much appreciated if it was answered asap, please and thank you! =D)

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
The equation 3.3x - 6.6 = 2.7x is equal to the expression 0.6x = 6.6 (2nd option)
You might be interested in
If sin theta = -1/2 and lies in the third quadrant, what is the cos?
never [62]
Sin angle that equals the 1/2 value is the 30 degree on the 1st Quadrant.

The angle of 30 degree on the 3rd Quadrant is equivalent to (formula and circle in the 1st photo) 180 + 30 = 210°.

So theta = 210° (3rd Quadrant) = 30° (1st Quadrant).

cos \: 30\degree = \sqrt{3} \div 2

Now just transfer the cos 30° to the 3rd Quadrant and the signal will be negative (as shown in the 2nd photo attached).

cos \: 210 \degree = - \sqrt{3} \div 2

5 0
4 years ago
Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu
kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

f(x) =  {x}^{5}  -  {x}^{3}  + 6

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

f'(x) = 5 {x}^{4} - 3 {x}^{2}

At turning point f'(x)=0.

5 {x}^{4} - 3 {x}^{2}  = 0

This implies that,

{x}^{2} (5 {x}^{2}  - 3) = 0

{x}^{2}  = 0 \: or \: 5 {x}^{2}  - 3 = 0

x =  - \frac{ \sqrt{15} }{5}   \: or \: x = 0 \:  \: or \: x =\frac{ \sqrt{15} }{5}

We plug this values into the original function to obtain the y-values of the turning points

(   -  \frac{ \sqrt{15} }{5}  , \frac{1}{125} ( 6 \sqrt{15}  +750)) \:and \:  (0, - 6) \: and\: (   \frac{ \sqrt{15} }{5}  , \frac{1}{125} ( - 6 \sqrt{15}  +750))

We now use the second derivative test to determine the absolute maximum minimum on the interval [-1,1]

f''(x) = 20 {x}^{3}  - 6x

f''( -  \frac{ \sqrt{15} }{5} ) \:   <  \: 0

Hence

(   -  \frac{ \sqrt{15} }{5}  , \frac{1}{125} ( 6 \sqrt{15}  + 750))

is a maximum point.

f''( \frac{ \sqrt{15} }{5} ) \:    >  \: 0

Hence

(     \frac{ \sqrt{15} }{5}  , \frac{1}{125} (- 6 \sqrt{15}  + 750))

is a minimum point.

f''(0) \: =\: 0

Hence (0,-6) is a point of inflexion

4 0
3 years ago
Help me asap (please please)
CaHeK987 [17]
Area of a circle = pi*r^2.

Here, A = 380.13 mi.  Unfortunately, "mi" is NOT a unit of area.

So I will assume that the problem should read   A = 380.13 sq. miles.
                                                                    380.12 mi^2
Thus,   380.13 mi^2 = 3.14*r^2, and r^2 = ------------------- 121.057 mi^2
                                                                           3.14

The radius is the sqrt of 121.057 mi^2:  11.00 miles.

The diam. is twice that, or d = 22.00 miles.



4 0
4 years ago
It took James 5h to paint an 8ft by 24ft wall. At this rate, how long would it take him to paint a 12ft by 36ft wall
olasank [31]
8 * 24 feet = 192 sq feet per 5 hours

12* 36 = 432 square feet

432 is 2.25 times the area of 192 square feet

So, it takes 5 * 2.25 = 11.25 hours


7 0
3 years ago
Help please explain in detail
yaroslaw [1]

Answer:

1. (n + 3)(5n + 8)

2. (x - 4)(7x - 4)

3. (k + 8)(7k + 1)

Step-by-step explanation:

1. We have to factorize 5n² + 23n + 24.

Now, 5n² + 23n + 24

= 5n² + 15n + 8n + 24

= 5n (n + 3) + 8 (n + 3)

=(n + 3)(5n + 8) (Answer)

2. We have to factorize 7x² - 32x + 16

Now,  7x² - 32x + 16

= 7x² - 28x - 4x + 16

= 7x (x - 4) - 4 (x - 4)

= (x - 4)(7x - 4) (Answer)

3. We have to factorize 7k² + 57k + 8

Now, 7k² + 57k + 8

= 7k² + 56k + k + 8

= 7k (k + 8) + 1 (k + 8)

= (k + 8)(7k + 1) (Answer)

4 0
3 years ago
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