Answer:
Park is <u>5 miles</u> from Billy's home.
Step-by-step explanation:
Given:
Billy left home at 9 a.m. And rode his bicycle to the park at an average speed of 10 miles per hour here and got the park at 9:30 a.m.
Now, to find the distance from park to Billy,s home.
Time it took Billy to rode his bicycle from park to home is from 9.30 a.m to 9.30 p.m.
So, the time = (9.30 - 9.00) = 30 minutes
Speed = 10 miles per hour.
Now, to get the distance from park to Billy's home we put formula:
Therefore, park is 5 miles from Billy's home.
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
Learn more about spring constant:
brainly.com/question/9199238
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Answer:
-60+87d
or
87d-60
Step-by-step explanation:
-3(20+-29d)=
-60+87d
The plans cost the same at 125 miles. the cost is $63.50
