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blagie [28]
3 years ago
6

An office manager reported that he spent $350 on gifts for employees. He said that $240 was spent on clothing with each man rece

iving a $20 T-shirt and each woman receiving a $40 sweatshirt. He said that $110 was spent on desk accessories with each man receiving a $5 calendar and each woman receiving a $15 stapler. If m equals the number of men and wequals the number of women, the system of equations that represents the expenses is as follows:
m+2w=12

m+3w=22

Solve the system, showing all steps, and then discuss the reasonableness of the answer.
Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

The correct answer is the solution of the system of equations are w = 10 and m = -8. The answer is not at all reasonable.

Step-by-step explanation:

The two system of equations are m + 2w = 12 and m + 3w = 22 where m and w represent the number of men and women working in an office.

We subtract both the sides with each other in order to solve the system of equation.

⇒ m + 3w - m - 2w = 22 - 12

⇒ w = 10.

⇒ m = -8.

The values of w and m are not reasonable at all. Since m and w represent the number of men and women in an office, they cannot be less than zero.

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Psychology students at Wittenberg University completed the Dental Anxiety Scale questionnaire (Psychological Reports, August 199
fredd [130]

Answer:

a) Z = 1.43

b) There is a 48.696% probability that someone scores between a 10 and a 15 on the Dental Anxiety Scale is

Step-by-step explanation:

Normal model problems can be solved by the zscore formula.

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

Each z-score value has an equivalent p-value, that represents the percentile that the value X is.

In our problem, the mean score was 11 and the standard deviation was 3.5.

So, \mu = 11, \sigma = 3.5.

(a) Suppose you score a 16 on the Dental Anxiety Scale. Find the z-value for this score.

What is the value of Z when X = 16?

Z = \frac{X - \mu}{\sigma}

Z = \frac{16 - 11}{3.5} = 1.43

(b) Find the probability that someone scores between a 10 and a 15 on the Dental Anxiety Scale.

We have to find the percentiles of both of these scores. This means that we have to find Z when X = 10 and X = 15. The probability that someone scores between a 10 and a 15 is the difference between the pvalues of the z-value of X = 10 and X = 15.

When X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 11}{3.5} = -0.29

Looking at the z score table, we find that the pvlaue of Z = -0.29 is 0.3859.

When X = 15

Z = \frac{X - \mu}{\sigma}

Z = \frac{15 - 11}{3.5} = 1.14

Looking at the z score table, we find that the pvlaue of Z = 1.14 is 0.87286.

So, the probability that someone scores between a 10 and a 15 on the Dental Anxiety Scale is

0.87286 - 0.3859 = 0.48696 = 48.696%

(c) Find the probability that someone scores above a 17 on the Dental Anxiety Scale

This probability is 100% minus the pvalue of the zvalue when X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 11}{3.5} = 1.71

When Z = 1.71, the pvalue is 0.95637. This means that there is a 95.637% probability that someone scores BELOW 17 on the dental anxiente scale.

100 - 95.637 = 4.363%

There is 4.363% probability that someone scores above a 17 on the Dental Anxiety Scale

4 0
3 years ago
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