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Neporo4naja [7]
3 years ago
10

Douglas invests money in two simple interest accounts. He invests three times as much in an account paying 14% as he does in an

account paying 5%. If he earns $152.75 in interest in one year from both accounts combined, how much did he invest altogether?
Mathematics
2 answers:
Igoryamba3 years ago
6 0

Answer:

Altogether, he invested $1300.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

He invests three times as much in an account paying 14% as he does in an account paying 5%.

I am going to call the earnings from the account paying 14% E_{1} and the earnings from the account paying 5% E_{2}. The principals are P_1 and P_{2}, in which P_{1} = 3P_{2}.

So

E_{1} = P_{1}*0.14t

E_{2} = P_{2}*0.05t

He earns $152.75 in interest in one year from both accounts combined.

This means that

E_{1} + E_{2} = 152.75

I am going to write E_{1} as a function of E_{2} and replace in the first equation, that of E_{1}.

So

E_{1} = 152.75 - E_{2}

E_{1} = P_{1}*0.14t

We also have that

P_{1} = 3P_{2}

So

152.75 - E_{2} = 3*P_{2}*0.14t

In which

E_{2} = P_{2}*0.05t

So

152.75 - P_{2}*0.05t = 0.42P_{2}t

His earnings are after 1 year, so t = 1

152.75 - P_{2}*0.05 = 0.42P_{2}

0.42P_{2} + P_{2}*0.05 = 152.75

0.47P_{2} = 152.75

P_{2} = \frac{152.75}{0.47}

P_{2} = 325

His smaller investment is 325.

P_{1} = 3P_{2} = 3*325 = 975

How much did he invest altogether?

This is P_{1} + P_{2}

P_{1} + P_{2} = 975 + 325 = 1300

Altogether, he invested $1300.

egoroff_w [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Let x represent the amount invested in the account paying 14% interest.

Let y represent the amount invested in the account paying 5% interest.

He invests three times as much in an account paying 14% as he does in an account paying 5%. This means that

x = 3y

The formula for simple interest is expressed as

I = (PRT)/100

Considering the account earning 14% interest,

I = (x × 14 × 1)/100 = 0.14x

Considering the account earning 5% interest,

I = (y × 5 × 1)/100 = 0.05y

If he earns $152.75 in interest in one year from both accounts combined, it means that

0.14x + 0.05y = 152.75 - - - - - - - - - -1

Substituting x = 3y into equation 1, it becomes

0.14(3y) + 0.05y = 152.75

0.42y + 0.05y = 152.75

0.47y = 152.75

y = 152.75!0.47

y = 325

x = 3y = 3 × 325

x = $975

Total amount of money invested is

975 + 325 = $1300

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Answer:

<h3>Mass of B in Kg = -558.44kg</h3>

Step-by-step explanation:

LET'S DO THIS!

Total mass of A, B and C = 1.95kg

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Mass of B = 4x the mass of c (4 x C) which is 4c

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<h3>Adding all together </h3>

700 + 4c + C = 1.95

<h3>Add like terms</h3>

700 + 5C = 1.95

5C = 1.95 - 700

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C = -698.05 ÷ 5

<h3>C = -139.61</h3>

<h3>To find B now </h3><h3>Remember they said B is 4 times the mass of C and C = -139.61</h3>

therefore B = 4 × -139.61

<h3>B = -558.44 kg </h3>

<h3>To check if we are correct, we add the masses of A, B and C to see if it equals their total mass which is 1.95kg</h3>

<h3>Using your calculator: </h3>

= 700 + ( -558.44 ) + ( -139.61 )

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Which makes us CORRECT ✅.

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Nutka1998 [239]

Check the picture below.

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anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

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Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

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The square difference of the zeroes is given by the expression.

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From the question, this difference is 169.

This implies that:

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