Answer:
Altogether, he invested $1300.
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.
He invests three times as much in an account paying 14% as he does in an account paying 5%.
I am going to call the earnings from the account paying 14%
and the earnings from the account paying 5%
. The principals are
and
, in which
.
So


He earns $152.75 in interest in one year from both accounts combined.
This means that

I am going to write
as a function of
and replace in the first equation, that of
.
So


We also have that

So

In which

So

His earnings are after 1 year, so 





His smaller investment is 325.

How much did he invest altogether?
This is 

Altogether, he invested $1300.