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Ymorist [56]
3 years ago
10

Helppp super simpleeeeeeeeeeeeeeeee

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0
The answer is “C” you have to look at the amount of pink lines
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2(8r+5)-3=4(4r-1)+11 is it an only solution or a no solution or infinite solution
pogonyaev

Answer:

Infinitely many solutions.

Step-by-step explanation:

Let's begin by carrying out the indicated multiplications, which must be done before any addition or subtraction:

2(8r+5)-3=4(4r-1)+11  becomes  16r + 10 - 3 = 16r - 4 + 11.

Subtracting 16r from both sides, we get 10 - 3 = - 4 + 11, or 7 = 7

This is always true, so we can conclude that this equation has infinitely many solutions.

3 0
2 years ago
Which property of multiplication is shown?<br><br> 9 × 0 − 6 × 0 = (9 − 6) × 0
JulsSmile [24]

Answer: Associative property

Step-by-step explanation: it is the same equation but they switched the numbers around on the other side of the equal sign so therefore its associative property

7 0
3 years ago
Read 2 more answers
translate the sentence into an equation. the sum of 4 times a number and 8 equals 7. use the variable c for the unknown number
jek_recluse [69]

Answer: 4× 8c = 7

Step-by-step explanation:

3 0
3 years ago
An online retailer is selling used books for ​$6.49​, and you have ​$50 to spend. How many books can you buy if you must pay 6.5
elena55 [62]
× all of the number that it tell you to do
4 0
3 years ago
Question Help Of 515515 samples of seafood purchased from various kinds of food stores in different regions of a country and gen
Setler79 [48]

Answer:

(0.5848 ; 0.6552)

We are confident that about 58% to 66% of sea foods in the country are Mislabelled.

No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

Step-by-step explanation:

Sample size, n = 51

p = 0.62

1 - p = 1 - 0.62 = 0.38

n = 515

Confidence level = 90% = Zcritical at 90% = 1.645

Confidence interval = (p ± margin of error)

Margin of Error = Zcritical * sqrt[(p(1-p))/n]

Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]

Margin of Error = 1.645 * 0.0214

Margin of Error = 0.035203

Lower boundary = (0.62 - 0.035203) = 0.584797

Upper boundary = (0.62 + 0.035203) = 0.655203

(0.5848 ; 0.6552)

We are confident that about 58% to 66% of sea foods in the country are Mislabelled.

No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

3 0
3 years ago
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