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3 years ago

Solve the equation. y + 6 = –3y + 26

Mathematics

2 answers:

stiks02 [169]3 years ago

4 0

Answer:

Step-by-step explanation:

3y+y = 26-6

4y = 20

4y/4 = 20/4

y = 5

Talja [164]3 years ago

3 0

Answer:

y = 5

Step-by-step explanation:

y + 6 = –3y + 26

Add 3y to each side

y+3y + 6 = –3y+3y + 26

4y +6 = 26

Subtract 6 from each side

4y+6-6 = 26-6

4y = 20

Divide by 4

4y/4 = 20/4

y = 5

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Stuck, anyone can help?

expeople1 [14]

Answer:

Step-by-step explanation:

$\sqrt{x-3}$ = x - 5 ( x ≥ 3 )

( $\sqrt{x-3}$ )² = ( x - 5 )²

x - 3 = x² - 10x + 25

x² - 11x + 28 = 0

(x - 4)(x - 7) = 0

$x_{1}$ = 7

$x_{2}$ = 4

Check the answer:

1). x = 7

$\sqrt{7-3}$ = 7 - 2

√4 = 2

2 = 2

2). x = 4

$\sqrt{4-3}$ = 4 - 5

1 = - 1 (False statement) ⇒ x = 4 is an extraneous solution.

6 0

3 years ago

The length of a rectangle is 8cm and the height is 16cm find the answer of the above figures using this formular...

notsponge [240]

Length=8cm
Breadth=16cm(Height)

<h3>Perimeter:-</h3>

$\\ \sf\longmapsto Perimeter=2(L+B)$

$\\ \sf\longmapsto Perimeter=2(16+8)$

$\\ \sf\longmapsto Perimeter=2(24)$

$\\ \sf\longmapsto Perimeter=48cm$

Area:-

$\\ \sf\longmapsto Area=Length\times Breadth$

$\\ \sf\longmapsto Area=8(16)$

$\\ \sf\longmapsto Area=128cm^2$

3 0

3 years ago

Sonji paid $25 for two scarves, which were different prices. When she got home she could not find the receipt. She remembered th

Oksanka [162]

Answer:

$14

Step-by-step explanation:

Make the variables:

x + 3

2x + 3 = 25

2x = 22

x = 11

11, 14

5 0

3 years ago

Read 2 more answers

Find the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one

ziro4ka [17]

The probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be 0.000343311 %

<h3>What is the probability?</h3>

Probability is synonymous with possibility. It is concerned with the occurrence of a random event.

Probability can only have a value between 0 and 1. Its simple notion is that something is very likely to occur. It is the proportion of favorable events to the total number of events.

No of failure,n = 7

No of trials,x≥6

A binomial probability is represented as;

$\rm P(x) = nC_x p^z(1-p)^{n-r}$

Substitute the given data;

$P(x \geq 6) = 7C_6 \times 9^6 \times 91-9)^{7-6} +7C_7 (9)^7+(1-9)^{(7-7)}$

$\rm P(x \geq 6) = 0.000000343311 \\\\ P(x \geq6)=0.000343311 \%$

Hence,the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be 0.000343311 %

To learn more about probability, refer to the link: brainly.com/question/795909.

#SPJ1

4 0

2 years ago

2. The National Safety Council routinely analyzes the benefit of seat belt use on driver safety. Their data showed that among 28

JulijaS [17]

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let $p_1$ = proportion of deaths when drivers were not wearing seat belts.

$p_2$ = proportion of deaths when drivers were wearing seat belts.

So, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of deaths when drivers were not wearing seat belts = $\frac{31}{2823}$ = 0.011

$\hat p_2$ = sample proportion of deaths when drivers were wearing seat belts = $\frac{16}{7765}$ = 0.002

$n_1$ = sample of drivers not wearing seat belts = 2823

$n_2$ = sample of drivers wearing seat belts = 7765

So, the test statistics = $\frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }$

= 4.438

The value of z test statistics is 4.438.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, Margin of error (E) = $1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }$

= $1.96 \times \sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} }$

= 0.00397

5 0

3 years ago