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3 years ago

10

Is there more humans than animals in the world

2 answers:

valentina_108 [34]3 years ago

8 0

Yes.There are more animals than humans in the world<u />

Anuta_ua [19.1K]3 years ago

5 0

There are many more animals than humans in the world.

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Beryllium has a nucleus composed of protons and neutrons. Given the data, how many neutrons are in a typical Beryllium nucleus?

son4ous [18]

16 because you multipy it first

5 0

3 years ago

Jesse is swinging Miguel in a circle at a tangential speed of 3.50 m/s. If the radius of the circle is 0.600 m and Miguel has a

vovangra [49]

Answer:

224.6 N

Explanation:

We can use first the formula to calculate the centripetal acceleration, given by:

$a_c=\frac{v_t^2}{R}$

where the Vt is the tangential velocity, and R is the radius of the circular motion.

Then, for our case we have:

$a_c=\frac{v_t^2}{R}=\frac{3.5^2}{0.6}\approx 20.42\,\,\frac{m}{s^2}$

And now we multiply this acceleration by Miguel's mass (11 kg) to obtain the centripetal force acting on him:

$F_c=11 \,*\,20.42\,N = 224.6\,\,N$

4 0

3 years ago

Read 2 more answers

Cómo puedo saber si el agua destilada que nos vendieron es destilada de verdad?

Pepsi [2]

Answer:

Caliente el agua del grifo hasta que se convierta en vapor. Cuando el vapor se vuelve a condensar en agua

Explanation:

7 0

3 years ago

Particles of m1 and m2 (m2>m1) are connected by a line in extensible string passing over a smooth fixed pulley. Initially, bo

Tresset [83]

Answer:

The velocity with which the mass will hit the floor is $v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.}$

Explanation:

If the tension in the string is $T$ , for $m_1$ we have

$T- m_1g =m_1a$ ,

and for the mass $m_2$

$T -m_2g = -m_2a$

From these equations we solve for $a$ and get:

$a =(\dfrac{m_2-m_1}{m_2+m_1}) g.$

The kinematic equation

$v_f^2 = v_0^2+2ax$

gives the final velocity $v_f$ of a particle, when its initial velocity was $v_0$ , and has traveled a distance $x$ while undergoing acceleration $a$ .

In our case

$v_0 = 0$ (the initial velocity of the particles is zero)

$a =(\dfrac{m_2-m_1}{m_2+m_1}) g.$

which gives us

$v_f^2 = 2ax$

$v_f^2 =2(\dfrac{m_2-m_1}{m_2+m_1}) g$

$\boxed{v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.} }$

which is the velocity with which the mass $m_2$ will hit the floor.

8 0

3 years ago

Two spaceships are observed from earth to be approaching each other along a straight line. Ship A moves at 0.40c relative to the

nirvana33 [79]

Answer:

0.80 c

Explanation:

The computation of speed is shown below:-

Here, The speed of the captain ship A report for speed of the ship B which is

$S = \frac{S_A + S_B}{1 + \frac{(S_AS_B)}{c^2} }$

where

$S_A$ indicates the speed of the ship A

$S_B$ indicates the speed of the ship B

and

C indicates the velocity of life

now we will Substitute 0.40c for A and 0.60 for B in the equation which is

$S = \frac{0.40c + 0.60c}{1 + \frac{(0.40c)(0.60c)}{c^2} }$

after solving the above equation we will get

0.80 c

So, The correct answer is 0.80c

5 0

3 years ago