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Pani-rosa [81]
3 years ago
15

A 5.0-kilogram sphere, starting from rest, falls freely 22 meters in 3.0 seconds near the surface of a planet.

Physics
1 answer:
Liono4ka [1.6K]3 years ago
8 0
<span>(3) one-half as great</span>;
Consider the relationship:
y_{f}-y_{i}=v_{i}t+ \frac{1}{2} at^{2}
with your data you get:
-22=0+ \frac{1}{2}a*9
a=-4.88m/s^{2}
approx <span>one-half</span> of <u />g=-9.8m/s^{2}
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goldfiish [28.3K]
    <span> Let’s determine the initial momentum of each car.
#1 = 998 * 20 = 19,960
#2 = 1200 * 17 = 20,400

This is this is total momentum in the x direction before the collision. B is the correct answer. Since momentum is conserved in both directions, this will be total momentum is the x direction after the collision. To prove that this is true, let’s determine the magnitude and direction of the total momentum after the collision.

Since the y axis and the x axis are perpendicular to each other, use the following equation to determine the magnitude of their final momentum.

Final = √(x^2 + y^2) = √(20,400^2 + 19,960^2) = √814,561,600

This is approximately 28,541. To determine the x component, we need to determine the angle of the final momentum. Use the following equation.

Tan θ = y/x = 19,960/20,400 = 499/510
θ = tan^-1 (499/510)

The angle is approximately 43.85˚ counter clockwise from the negative x axis. To determine the x component, multiply the final momentum by the cosine of the angle.

x = √814,561,600 * cos (tan^-1 (499/510) = 20,400</span>
3 0
3 years ago
What are the characteristics of high energy wave?
Ivahew [28]

Answer:

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8 0
2 years ago
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Answer:

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Fair enough, but you'll have to tell us the volume of the bar first.
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<span>An electrons moves at 2.0x10^6 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.4x10^-2 T. 

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