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luda_lava [24]
3 years ago
12

Two wheels, each with the same radius R and the same total mass M, are rotating about their fixed axles. Wheel A is a hoop with

all the mass very near the rim. Wheel B is a disk with the mass spread out uniformly. Which has the larger moment of inertia?
Physics
1 answer:
likoan [24]3 years ago
3 0

Answer:

Wheel A

Explanation:

Moment of inertia is the tendency of a body to resist angular acceleration.

The moment of inertia of a body having its mass concentrated away from the axis of rotation will have a higher value.

<u>For a ring, we have the moment of inertia as:</u>

I=m.r^2

where:

m = mass of the ring

r = radius of the ring

<u>Moment of inertia for a disc:</u>

I=\frac{1}{2} m.r^2

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In a displacement versus time graph, what does the slope of a line at any point indicate?
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In a displacement versus time graph, the slope of the line at any point on the graph indicates the <em>magnitude of velocity</em>.  

(It can't indicate velocity completely, because the graph shows nothing about the direction of the motion.)

4 0
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A student walks 4 block east, 7 blocks west, 1 blocks east then 2 blocks west in an hour. Her average speed is____ block/hour
Gemiola [76]

Average speed = (total distance) / (total time)

Average speed = (4+7+1+2 blox) / (1 hour)

<em>Average speed = 14 blocks/hour</em>

<em></em>

I'm gonna go out on a limb here and take a wild guess:

I'm guessing that there's another question glued onto the end of this one, and it asks you to find either her displacement or her average velocity.  I'm so sure of this that I'm gonna give you the solution for that too.  If there's no more question, then you won't need this, and you can just discard it.  I won't mind.

Average velocity = (displacement) / (time for the displacement)

"Displacement" = distance and direction from the start point to the end point, regardless of how she got there.

Displacement = (4E + 7W + 1E + 2W)

Displacement = (5E + 9W)

<em>Displacement = 4 blocks west</em>

Average velocity = (4 blocks west) / (1 hour)

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4 0
2 years ago
We have three identical metallic spheres A, B, C. Initially sphere A is charged with charge Q, while B and C are neutral. First,
larisa [96]

Answer:

The final charges of each sphere are:   q_A = 3/8 Q , q_B = 3/8 Q ,               q_C = 3/4 Q

Explanation:

This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.

Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point

                q_A = Q / 2

                q_B = Q / 2

Now sphere A touches sphere C, ending with half the charge

                q_A = ½ (Q / 2) = ¼ Q

                q_B = ¼ Q

Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge

                  q = Q / 4 + Q / 2 = ¾ Q

This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q

                  q_A = 3/8 Q

                  q_B = 3/8 Q

The final charges of each sphere are:

                q_A = 3/8 Q

                q_B = 3/8 Q

                q_C = 3/4 Q

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Answer:

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