Answer:
The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.
Explanation:
Given that,
Mass of bucket = 54 kg
Radius = 0.050 m
We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder
Using formula of torque
Where, m = mass
g = acceleration due to gravity
r = radius
Put the value into the formula
Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.
Answer:
Explanation:
His displacement is 0 because he ended up exactly where he started.
<u><em>
Working of Electric Geyser:
</em></u><em>
simply in our homes ,, in electric geysers electric energy is converted into heat energy ,, when cold water enters into the geyser through inlet then it is heated into a container inside the geyser,,when it is heated connection of electricity is cut off inside the geyser,,
</em><em>then this hot water comes out through a outlet ... :)</em>
<h3>Answer</h3>
6.6 N pointing to the right
<h3>Explanation</h3>
Given that,
two forces acting of magnitude 3.6N
angle between them = 48°
To find,
the third force that will cause the object to be in equilibrium
<h3>1)</h3>
Find the vertical and horizontal components of the two forces
vertical force1 = sin(24)(3.6)
vertical force2= -sin(24)(3.6)
<em>(negative sign since it is acting on opposite direction)</em>
vertical force3 = sin(24)(3.6) - sin(24)(3.6)
= 0
<h3>2)</h3>
horizontal force1 = cos(24)(3.6)
horizontal force2= cos(24)(3.6)
horizontal force3 = cos(24)(3.6) + cos(24)(3.6)
= 2(cos(24)(3.6))
= 6.5775 N
≈ 6.6 N
<em />
<em />
Speaking bout mass,
it's mass is still 40Kg on the moon
but it's Weight on the moon is 1/6mg
