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3 years ago

A model train traveling at a constant speed around a circular track has a constant velocity

Physics

2 answers:

aleksandrvk [35]3 years ago

8 0

It is true thats the correct andrea

Mrac [35]3 years ago

7 0

The answer should be yes

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When an ideal gas does positive work in its surroundings, which of the ga's quantities increases?

Burka [1]

I think it's B hope it helps

4 0

3 years ago

21. For this table of data, how should the y-axis be labeled (with units)?

Snowcat [4.5K]

Answer:

The y-axis would be labeled with displacement (m)

Explanation:

The displacement is dependent on the force applied.

Labels should have what you measure and how your units of measure.

The x-axis would be labeleed with force applied (N)

The y-axis would be labeled with displacement (m)

8 0

2 years ago

In the Hunger Games movie, Katniss Everdeen fires a 0.0200-kg arrow from ground level to pierce an apple up on a stage. The spri

egoroff_w [7]

Answer:

a) $v=99.8584\ m.s^{-1}$

b) $v'=99.366\ m.s^{-1}$

Explanation:

Given:

mass of the arrow, $m=0.02\ kg$

stiffness constant of the bow, $k=330\ N,m^{-1}$

distance of pulling back the arrow on the bow from its mean position, $\Delta x=0.55\ m$

height of the apple targeted, $h=5\ m$

Force on the arrow due to the stiffness of the bow:

$F=k.\Delta x$

$F=330\times 0.55$

$F=181.5\ N$

Now the acceleration of the arrow upwards:

$a=\frac{F}{m}$

$a=\frac{181.5}{0.02}$

$a=9075\ m.s^{-2}$

a) For the course of motion when the arrow leaves the bow after the stretch is relaxed we consider that the arrow left the bow after its string goes to the mean position. During this phase the arrow also faces gravity in the downward direction.

Using the equation of motion:

$v^2=u^2+2(a-g).\Delta x$

where:

$v=$ velocity with which the arrow leaves the bow

$u=$ initial velocity of the arrow after it left

$v^2=0^2+2\times (9075-9.81)\times 0.55$

$v=99.8584\ m.s^{-1}$

b) Now when the arrow travels up then it is under a constant gravitational force acting opposite to the motion.

Using eq. of motion:

$v'^2=v^2-2\times g.h$

where:

$v'=$ final velocity when the arrow hits the target

$v=$ initial velocity after the arrow has been launched

$v'^2=99.8584^2-2\times 9.81\times 5$

$v'=99.366\ m.s^{-1}$

3 0

3 years ago

What are three properties of magnets

EleoNora [17]

Attractive Property – Magnet attracts ferromagnetic materials like iron, cobalt, and nickel.
Repulsive Properties – Like magnetic poles repel each other and unlike magnetic poles attract each other.
Directive Property – A freely suspended magnet always points in a north-south direction.

Have a good day!

7 0

3 years ago

A man standing on a bridge throws a stone horizontally with a speed of 20m/s. The stone hits the water below 3 seconds later. Ho

SpyIntel [72]

h = 1/2 * g t^2
= 1/2 * 9.8 * 3^2
= 44.1 m

d = vx * t = 20 * 3 = 60 m
Ans: 44.1 m, 60 m

4 0

2 years ago

Read 2 more answers