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Sergio039 [100]
3 years ago
8

A model train traveling at a constant speed around a circular track has a constant velocity

Physics
2 answers:
aleksandrvk [35]3 years ago
8 0
It is true thats the correct andrea
Mrac [35]3 years ago
7 0
The answer should be yes
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A car is traveling at 21m/s. It accelerates at 1.4m/s2 for 11s. How fast is the car moving after the acceleration?
nata0808 [166]

Answer:

v=u+at

v=21+1.4(11)

v=21+15.4

v=36.4

3 0
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A magnetically soft material is placed in a strong magnetic feild. what is the most likely outcome?
myrzilka [38]
So we want to know what will happen if we put a magnetically soft material in a strong magnetic field. A magnetically soft material is a material whose magnetic field can easily be reversed. Those are ferromagnetic materials. Iron is such a material. When a magnetically soft material is placed into a strong magnetic field it gets its own magnetic field. But its not a permanent magnetic field, it can be changed by a different strong magnetic field. 
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3 years ago
If a puddle of water is frozen, do the particles in the ice have kinetic energy? Explain.
TEA [102]
They have some but not very much, the particles in the ice are still vibrating just not as much as in water. the only time a substance would have 0 kinetic energy is when that substance is at 0 degrees kelvin(absolute zero) so far no place in the universe has been recorded at absolute zero though
8 0
3 years ago
The distance, x, covered by a particle in time, t, is given as x=a +bc+ct^2 +dt^3
Sav [38]

Answer:

a has units of distance

b  has units of distance over time

c  has units of distance over time^2

d has units of distance over time^3

Explanation:

Since the expression for the distance is:

x = a+b\,t+c\,t^2+d\,t^3

then:

a has units of distance

b  has units of distance over time

c  has units of distance over time^2

d has units of distance over time^3

because we are supposed to be able to add all of the terms and get a distance.  So the products on each term that contains factors of time (t) should be cancelling those time units with units in the denominator of the multiplicative constant s that accompany them.

6 0
3 years ago
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mestny [16]

Answer:bsnz

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3 years ago
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