3 years ago

Is it an identity? and how?

1 answer:

6 0

Yes, it's an identity because remember sin 6x would be (3x + 3x)= which would make it 2 sin 3x....concluding the equation should be an identity. :)

Hoped this helped :)

You might be interested in

Shana is forming kickball teams out of all of the students that signed up from two schools. Each team must have the same number

V125BC [204]

Needs more info!!!!!!

6 0

3 years ago

Read 2 more answers

The Marked price of a jacket at a dealer's shop is 2400. The dealer allows a discount of 15% to the retailer. As the company's p

Andrej [43]

Answer:

2400

2640

360

Step-by-step explanation:

the retailer has to sell it for the same price as the dealer.

so, both mark it for 2400 sale price.

if a customer buys it at the retailer, the retailer makes the 15% discount he got from the dealer as profit.

2400 = 100%

1% = 2400/100 = 24

15% = 24×15 = 360

the retailer makes this profit no matter what other fees or taxes are added.

the final price is then including 10% VAT

2400 = 100%

10% = 24×10 = 240

final price = SP + VAT = 2400 + 240 = 2640

6 0

3 years ago

Please help im 25% blind

FrozenT [24]

Answer:

Step-by-step explanation: all you have to do is work it out

5 0

2 years ago

The quotient rule for exponents states that bm bn=_______, b≠0 . When dividing exponential expressions with the same nonzero b

wariber [46]

Answer:

The quotient rule for exponents states that $b^{m}\div b^{n}=b^{m-n}$ .

When dividing exponential expressions with the same nonzero base, <u>subtract</u> the exponents.

Step-by-step explanation:

Some rules to solve exponents are:

$x^{0}=1$
$(x^{m})^{n}=x^{mn}$
$x^{-n}=\frac{1}{x^{n}}$
$x^{m}\cdot x^{n}=x^{m+n}$
$\frac{x^{m}}{x^{n}}=x^{m-n}$

The quotient rule for exponents states that:

$b^{m}\div b^{n}=b^{m-n}$ .

When dividing exponential expressions with the same nonzero base, <u>subtract</u> the exponents.

3 0

3 years ago

Is Q the midpoint or PR? please justify the answer

mezya [45]

Since PQ=PR
=> Q is the midpoint of PR
Hope this helps you

6 0

3 years ago