Answer:
An identity matrix, is a matrix that have '1' in the main diagonal. All of the other terms are '0'. When you multiply any matrix by the identity matrix, the result is the same matrix that you multiplied.
Example:
![\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
In the set of the real number is the same that the application of identity property.
Every number multiplied by 1 es the same number.
Step-by-step explanation:
The answer Its 4.5281 ....etc
Answer:
infinite solutions
Step-by-step explanation:
3(n+6)≥3n+8
3n+18≥3n+8 (distributive property)
18≥8 (subtracted 3n from both sides)
this will always be true so there are infinite solutions
A(−2, 6) ⇒⇒⇒ <span>A′(1, 6)
</span>B(2, 6) ⇒⇒⇒ <span>B′(5, 6)
</span>C(2, 4) ⇒⇒⇒ <span>C′(5, 4)
</span>D(−2, 4) ⇒⇒⇒ D′(1, 4)
By comparing the coordinates of points and its images we can deduce the rule of the transformation which is :
(x , y ) ⇒⇒⇒ ( x + 3 , y )
So, the <span>rectangle is transformed 3 units to the right.</span>
Answer:
This would be a regular polygon.
Step-by-step explanation:
A regular polygon has congruent sides and interior angles.
An irregular polygon does not have congruent sides and all interior angles.
A convex polygon does not have a interior angle greater than 180°.
Lastly, a concave polygon has only one interior angle greater than 180°.
Using the process of elimination, it would not be a convex or concave polygon. Now we have either a regular or irregular polygon. This polygon can not be a irregular polygon because all the sides are congruent. This means that this polygon is a regular polygon!
