Answer:
1. Use a straightedge
2. Draw dots on the line to mark the starting point
3. Place the point of the compass on the point you made or was given
4. Extend the compass so that the pencil is on the 2nd point & make a an arc thru point B
5. Place the compass point on the starting point dot on the line and draw w/ the pencil to create an arc crossing the line.
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Slope of AB = 1/3 and slope of BC = -3 so these 2 lines are perpendicular
The same is true for all the other adjjacent pairs of lines.
Oppoitse lines are also paralllel ( slope of AB = 1/3 and slope of DC = 1/3) and other pair are both of slope -3.
So Its C
11 cow and 19 chicken 11*4=44 19*2=38 38+44=82
