The answer is <span>13584.1129633 which simplified is 13584 :)</span>
Answer:
A
Step-by-step explanation:
Subtract 1 from both sides and divide by 2. This will leave you with x=-2 which is the simplified form of the equation.
Answer:
The probability that the sample mean would differ from the population mean by greater than 0.8 kg is P=0.3843.
Step-by-step explanation:
We have a population with mean 60 kg and a variance of 100 kg.
We take a sample of n=118 individuals and we want to calculate the probability that the sample mean will differ more than 0.8 from the population mean.
This can be calculated using the properties of the sampling distribution, and calculating the z-score taking into account the sample size.
The sampling distribution mean is equal to the population mean.
The standard deviation of the sampling distribution is equal to:
We have to calculate the probability P(|Xs|>0.8). The z-scores for this can be calculated as:
Then, we have:
Y=mx+b
x=number of newspapers
37.5 earned for 5 newspapers
37.5=5m+b
earned 75 and deliverd 20 newpapers
75=20m+b
we have
37.5=5m+b and
75=20m+b
multiply first equaiton by -1 and add to other equaiton
-37.5=-5m-b
<u>75=20m+b +</u>
37.5=15m+0b
37.5=15m
divide both sides by 15
2.5=m
sub back to find b
75=2.5(20)+b
75=50+b
minsu 50 both sides
25=b
y=2.5x+25 is lnear funtion