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dolphi86 [110]
3 years ago
5

Stock market question ASAP

Mathematics
1 answer:
Ksju [112]3 years ago
4 0
It is an exponential growth and the growth factor is 1.7 per day. I got this answer because after subtracting 103.70 and 61, I added the difference to 103.70, but the sum wasn't 176.29 so it has to be exponential. After figuring out that it was exponential I divided 103.70 and 61 to get 1.7 and double checked by multiplying 103.70 and 1.7 to get 176.29. Sorry this is so lengthy just wanted to make sure you understood for other questions.
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A delivery truck made 8 stops in one neighborhood. By stop 5, there were 11 packages delivered. This graph shows this informatio
IceJOKER [234]
2 delivery stops

Find the point that hits 5 on the "packaging delivery".

Then look down to find the 'x'

your x is 2

hope this helps
6 0
3 years ago
What is 30 less than 4 times a number is equal to 14
Genrish500 [490]
The answer is x=11
4x-30=14
You add 30 to each side=4x=44
Then you divide 44 by 4 which=11
4 0
3 years ago
(3a^2+b^4)^3/ 2a^3 b^3) ^2
mezya [45]

(Answer included in imagine)

3 0
2 years ago
There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f
Ann [662]

Answer:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated population proportion for this case is:

\hat p = \frac{350}{500}=0.7

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0
2 years ago
Solve for n: 3(n+6)≥3n+8
hodyreva [135]

Answer:

infinite solutions

Step-by-step explanation:

3(n+6)≥3n+8

3n+18≥3n+8 (distributive property)

18≥8 (subtracted 3n from both sides)

this will always be true so there are infinite solutions

7 0
3 years ago
Read 2 more answers
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