1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gladu [14]
3 years ago
14

Give three importance of PH in our daily life?​

Chemistry
2 answers:
german3 years ago
6 0

\bold{ANSWER}

▶To check the nature of food items.

▶To check the nature of soil .

Likurg_2 [28]3 years ago
3 0

_____________________________

Answer:

1. Living organisms and plants survive in neutral medium.

2. Plants grow or survive in neutral medium that is soil should be neutral. It is the soil is acidic, farmer uses lime as a basic to make the soil neutral and if the soil is a basic, farmer uses cow dung cakes as a acidic medium which neutralizes the soil and make soil neutral.

3. Animals survive only in neutral water, what is it rain makes the water body is acidic which causes aquatic animals die.

_____________________________

You might be interested in
Which of the following is NOT an example of a molecule <br> A: H2O2<br> B:NCI3<br> C:F<br> D:O3
timama [110]

C. F because it's an atom not a molecule

6 0
3 years ago
Read 2 more answers
If 11g of a gas occupies 5.6dm'3at s.t.p., calculate it's vapour density (1.0mol of a gas occupies 22.4dm'3at s.t.p.).​
11111nata11111 [884]

Answer:

{ \boxed{ \bf{vapour \: density = 2 \times molecular \: mass}}} \\{ \tt{ PV= (\frac{m}{ m_{r}}) RT}} \\ { \tt{3 \times 5.6 =  \frac{11}{m _{r}}  \times 0.0831 \times 273}} \\ { \tt{m _{r} = 14.85 \: g}} \\  \\ { \bf{vapour \: density = 2 \times m _{r}}} \\  = 2 \times 14.85 \\  = 29.7 \: { \tt{g {dm}^{ - 3} }}

7 0
3 years ago
Identify whether this describes heat or temperature.<br> Unit of measurement: Celsius
tresset_1 [31]

Answer:

temperature

Explanation:

Celsius is a unit of temperature. Another example of this would be Kelvin or Fahrenheit.

6 0
2 years ago
What is the speed of light of an orange light with a wavelength of 600nm and a frequency of 5.00x1014?
vovangra [49]

Answer:

3 × 10^8 m/s

Explanation:

The wavelength, can be calculated by using the following formula;

λ = v/f

Where;

λ = wavelength (m)

v = velocity/speed of light (m/s)

f = frequency (Hz)

According to the provided information in this question, λ = 600nm i.e. 600 × 10^-9m, f = 5.00 x 10^14 Hz

Hence, using λ = v/f

v = λ × f

v = 600 × 10^-9 × 5.00 x 10^14

v = 6 × 10^-7 × 5.00 x 10^14

v = 30 × 10^(-7 + 14)

v = 30 × 10^ (7)

v = 3 × 10^8 m/s

3 0
2 years ago
Why do you need a correct lewis structure before you can use vsepr to predict a molecules geometry.
JulsSmile [24]

Answer:

so the answer that you get isn't wrong? i dont know

4 0
2 years ago
Other questions:
  • What is the concentration of a solution prepared by placing 20. mL of 0.12 M K2S in a graduated cylinder and pouring water until
    12·1 answer
  • When phenolphthalein indicator is added to a colorless solution with a pH of 10, a student observes and concludes that the teste
    8·1 answer
  • A 24.00 mL sample of a solution of Pb(ClO3)2 was diluted with water to 52.00 mL. A 17.00 mL sample of the dilute solution was fo
    15·1 answer
  • Which of the following has the correct change in enthalpy and reaction description for the following reaction? NH3(g) + HCl(g) N
    9·2 answers
  • I don't know any of these Chem 1 questions
    11·1 answer
  • Pleaseeeeee help I Will mark brainliest
    9·1 answer
  • Find the initial temperature of Aluminum if 35 g of it produces 781.2 Joules at the final temperature of 44.3 ºC.
    7·1 answer
  • Given the equation representing a system at equilibrium:Which statement describes the concentration of the two gases in this sys
    8·1 answer
  • PLZ HELP I WILL GIVE BRAINLIST ITS DUE IN AN HOUR
    8·1 answer
  • How many carbon monoxide molecules are in 0.75 moles of carbon monoxide?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!