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3 years ago

[Timed] Which type of reaction does this diagram represent?

Chemistry

2 answers:

IRINA_888 [86]3 years ago

5 0

Nuclear fission because an atom is splitting....

emmasim [6.3K]3 years ago

5 0

Answer:

nuclear fission because an atom is splitting into two large fragments of comparable mass

Explanation:

because if you add the numbers they all equal the original mass

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What is the maximum number of electrons that an atomic orbital can contain?<br> 2<br> 1<br> 8<br> 32

zavuch27 [327]

Answer:

Explanation:

google

4 0

3 years ago

Based on the table, which do you think is larger – your direct water use or your indirect water use?

Pavlova-9 [17]

Answer:

your indirect water use.

5 0

3 years ago

Let us write the appropriate equilibria and associate the correction <img src="https://tex.z-dn.net/?f=K_b" id="TexFormula1" tit

rosijanka [135]

Explanation:

The relation between $K_a\&K_b$ is given by :

$K_w=K_a\times K_b$

Where :

$K_w=1\times 10^{-14}$ = Ionic prodcut of water

The value of the first ionization constant of sodium sulfite = $K_{a1}=1.4\times 10^{-2}$

The value of $K_{b1}$ :

$1\times 10^{-14}=1.4\times 10^{-2}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{1.4\times 10^{-2}}=7.1\times 10^{-13}$

The value of the second ionization constant of sodium sulfite = $K_{a2}=6.3\times 10^{-8}$

The value of $K_{b2}$ :

$1\times 10^{-14}=6.3\times 10^{-8}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{6.3\times 10^{-8}}=1.6\times 10^{-7}$

3 0

3 years ago

A solution is made by mixing 37.g of thiophene C4H4S and 72.g of heptane C7H16. Calculate the mole fraction of thiophene in this

guajiro [1.7K]

Answer:

0.38

Explanation:

Molar mass of thiophene= 84g/mol

Mass of thiophene = 37g

Number of moles= 37/84= 0.44 moles

Molar mass of heptane= 100 g/mol

Mass of heptane = 72g

Number of moles = 72/100= 0.72 moles

Total number of moles= 0.44 + 0.72= 1.16 moles

mole fraction of thiophene = 0.44/1.16= 0.38

4 0

3 years ago

Please help me outttt

leonid [27]

Answer:

4.) 9, 1, and 4 5.) 4, 1, and 4

Explanation:

I am not quite sure about this because I cannot remember if the coefficient (the number before the elements) is applied to every element in the compound. If it is then your number of atoms are as follows: CORRECTION: you do not have to apply the coefficient to every element only the one that is after it. So when you back and fix the error your number of atoms will be as follows:

number 4

H: 9

P: 1

O: 4

number 5:

H: 4

S: 1

O: 4

you can calculate the number of atoms present in this compound by multiplying the coefficient and the subscripts of each atom.

hope this helped you :)

7 0

3 years ago