May someone please help me with this Math problem, Thank you

Mathematics

1 answer:

Semmy [17]3 years ago

8 0

Answer:

c. 10

Step-by-step explanation:

Eliminate parentheses using the distributive property.

3(b+4) -2(2b+3) = -4 . . . . given

3b +12 -4b -6 = -4 . . . . . parentheses eliminated

-b +6 = -4 . . . . . . . . . . . . collect terms

-b = -10 . . . . . . . . . . . . . . subtract 6

b = 10 . . . . . . . . . . . . . . . . multiply by -1

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The rules of equality require that any operation you perform on one side of the equal sign must also be done on the other side. So when we say "subtract 6", we assume you know that means "subtract 6 from both sides of the equation", for example.

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Can anyone please help me with 1,2,&,3 ?

Serhud [2]

Okay, lets start with number 1.

$(x+3)^{3}$ is also equal to (x+3)(x+3)(x+3)

If you take the first two ones and multiple them out it ends up with $x^{2} + 3x +3x + 9$ or also know as $x^{2} + 6x + 9$

You see to multiply them you take the first number in the first group of parenthesis and use the distributive property on the second equation, then you do the same this but with the second number in the first equation.

So once you have $(x^{2} + 6x + 9)$ you multiply it with your remaining (x + 3) using the distributive property to get $x^3 + 9x^2 + 27x + 27$