All categories

3 years ago

In triangle PQR, line PO bisects

Mathematics

1 answer:

Valentin [98]3 years ago

5 0

15.

To find this, here is the work in the photo attached:

You might be interested in

A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to

melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

$P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}$

Mean of X:

$E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42$

Variance of X:

$E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}$

$var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58$

5 0

3 years ago

1. Trey bought a puzzle priced at $12 and a

Mazyrski [523]

Answer:

$28.08

Step-by-step explanation:

104%×12+104%×15

=$28.08

Hope this helps!!!

7 0

3 years ago

Read 2 more answers

The scores on a psychology exam were normally distributed with a mean of 60 and a standard deviation of 10 . A failing grade on

tensa zangetsu [6.8K]

Answer:

The cutoff for a failing score was 40,

Approximately 2.3% of the students failed.

Step-by-step explanation:

Given,

Mean, $\mu=60$

Standard deviation, $\sigma=10$

Let x represents the cutoff for a failing score,

Thus, according to the question,

$\frac{x-\mu}{\sigma}=-2$

$\frac{x-60}{10}=-2$

$x-60=-20$

$x=-20+60$

$x=40$

Thus, the cutoff for a failing score is 40,

∵ P(<-2) = 0.02275 = 2.275 % ≈ 2.3 %

Hence, Approximately 2.3 % of the students failed. 

7 0

3 years ago

the area of one face of a cube is 36 sq feet. what is the volume of a cube that had edges that are twice as long?

noname [10]

The cube with 1 face with area 36 ft^2 has an edge of 6 ft.

The other cube has edges 2 * 6 = 12 ft long and its volume is 12^3

= 1728 ft^3 (answer).

6 0

3 years ago

Help ASAP ill mark brainliest

Klio2033 [76]

Answer:

54:73

Step-by-step explanation:

There is more 54's then any other number

73 is the median

6 0

2 years ago