Y ~ Po (λ)
P(Y < 2) = P(Y ≤ 1) = 0.04
Plug into the pdf for Po(λ), and solve for λ
After that, use your answer to find P(Y > 5)
Step-by-step explanation:
1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....
= Solution ,
Length ( L ) = ?
breadth ( b ) = 10xy cm
area ( a ) = ( 30x² + 20xy )
Now ,
area ( a ) = l × b
or, ( 30x²y + 20xy ) = L × 10xy cm



2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.
= Solution,


The product of 3x and 4y = 6xy
= 6x - 4xy

hope it helped !!!!
[ ( x + 4 )( x + 5 ) + 4( x + 1 )( x + 5) - 5( x + 1 )( x + 4 ) ] / [( x + 1 )( x + 4)( x + 5 )] = ( x^2 + 9x + 20 + 4x^2 + 24x +20 - 5x^2 - 25x - 20) / [( x + 1 )( x + 4)( x + 5 )] =
( - 2x + 20 ) / [( x + 1 )( x + 4)( x + 5 )] = ( - 2)( x - 10) / [( x + 1 )( x + 4)( x + 5 )]
0.99 if you round up it will just be 1
An equation without exponents and two variables, is typically a straight line. All the points on the line with integer coordinates are solutions of the equation. Since x and y have to be positive as well, there aren't that many solutions.
Let's see where the line crosses the x-axis, it is where y=0:
x/0.5 + 0 = 18, so x=9 at the intercept. y=0 there, so this is a point on the line, but not a solution to the question (y was supposed to be positive).
Possible values for x are thus limited to 1,2,3,4,5,6 and 7. You can try them all (ie., solve the equation with them) and see for which x values the y is also positive and integer.
You will find that x=4, y=2 is the only pair that satisfies these conditions.