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Vikentia [17]
4 years ago
10

Which of the following is equal to 7 1/4? Show work. Please help.

Mathematics
2 answers:
kolezko [41]4 years ago
7 0

Answer:

C)  \sqrt[4]{7}.

Step-by-step explanation:

Given : 7^{\frac{1}{4}}.

To find : Equivalence expression.

Solution : we have given that 7^{\frac{1}{4}}.

By the radical rule  \sqrt[n]{x} = x^{\frac{1}{n}}

Then  7^{\frac{1}{4}} =  \sqrt[4]{7}.

Therefore, C)  \sqrt[4]{7}.

fomenos4 years ago
6 0

d because you take the denominator of the fraction and you put it infront of the square root then you take the numerator and multiply it by the number at hand in this case 7


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3 years ago
The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length.
emmasim [6.3K]

Step-by-step explanation:

1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....

= Solution ,

Length ( L ) = ?

breadth ( b ) = 10xy cm

area ( a ) = ( 30x² + 20xy )

Now ,

area ( a ) = l × b

or, ( 30x²y + 20xy ) = L × 10xy cm

or,\frac{30 {xy + 20xy}^{2} }{10xy}  = l \\

or, \: l = 3 {x}^{2 - 1}  + 2cm

\boxed{\sf{l = (3x+2)cm}}

2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.

= Solution,

= \frac{20 {x}^{4} {y}^{2}  }{5 {x}^{3} y}   \\

= 4xy

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hope it helped !!!!

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%2B1%7D%20%2B%20%5Cfrac%7B4%7D%7Bx%2B4%7D%20-%20%5Cfrac%7B5%7D%7Bx%2B5%3C
Anna11 [10]
[ ( x + 4 )( x + 5 ) + 4( x + 1 )( x +  5) - 5( x + 1 )( x + 4 ) ] / [( x + 1 )( x +  4)( x + 5 )] = ( x^2 + 9x + 20 + 4x^2 + 24x +20 - 5x^2 - 25x - 20) / [( x + 1 )( x +  4)( x + 5 )] =
( - 2x + 20 ) /  [( x + 1 )( x +  4)( x + 5 )] = ( - 2)( x - 10) / [( x + 1 )( x +  4)( x + 5 )]
4 0
3 years ago
Let tan x = 2.4, sin y = 0.6, and both x and y be between 0° and 90°. Then cos(x + y) equals?
ZanzabumX [31]
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If x/0.5 + y/0.2 = 18, where x and y are positive integers, then what is the value of x ?
dem82 [27]
An equation without exponents and two variables, is typically a straight line. All the points on the line with integer coordinates are solutions of the equation. Since x and y have to be positive as well, there aren't that many solutions.

Let's see where the line crosses the x-axis, it is where y=0:

x/0.5 + 0 = 18, so x=9 at the intercept. y=0 there, so this is a point on the line, but not a solution to the question (y was supposed to be positive).

Possible values for x are thus limited to 1,2,3,4,5,6 and 7. You can try them all (ie., solve the equation with them) and see for which x values the y is also positive and integer.

You will find that x=4, y=2 is the only pair that satisfies these conditions.

7 0
3 years ago
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