10 x 10 = 100
20 + 20 + 20 + 20 +20 = 100
4 x 25 = 100
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
9.2
Step-by-step explanation:
Use law of sines
a/sinA = b/sinB
5/sin 31 = b/sin 108
b=9.2
D)One solution. b=5
Distribute 2 times b plus 2 times 3
2b+6
2b+6+2b=26
Combine like terms 4b+6=26
Subtract 6 from both sides
4b=20
Divide both sides by 4
b=5
Check by substituting 5 for b
2 (5+3)+2(5)=26
2(8) + 2(5)=26
16+10=26
26=26
Realmente no entiendo esta pregunta, lo siento mucho, pero espero que lo resuelvas. Lo siento, nuevamente..
