Let the number of raspberry bushes in one garden = x
And the number of raspberry bushes in second garden = y
Garden one has 5 times as many raspberry bushes as second garden,
So the equation will be,
x = 5y -------(1)
If 22 bushes were transplanted from garden one to the second, number of bushes in both the garden becomes same,
Therefore, (x - 22) = (y + 22)
x - y = 22 + 22
x - y = 44 ------(2)
Substitute the value of x from equation (1) to equation (2)
5y - y = 44
4y = 44
y = 11
Substitute the value of 'y' in equation (1),
x = 5(11)
x = 55
Therefore, Number of bushes in garden one were 55 and in second garden 11 originally.
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Answer:
(-13m - 1)/(n + 5).
Step-by-step explanation:
-5m-9/n+5 + -8m+8/n+5
The denominators are the same so we add the numerators:
= (-5m - 9 - 8m + 8 / (n + 5)
= (-13m - 1)/(n + 5).
<span><span><span><span>Simplify: x+3/</span>9</span><span><span>x / x+12/</span><span>x+6</span></span></span>
Rewrite the equation by multiplying the reciprocal of </span>
<span><span>x+12/<span>x+6
</span></span><span><span>Now the problem will be as follows, x+3</span>/9</span> ×<span> 6<span>/x+12
The answer is 2(x + 3) / 3 (x + 12).
</span></span></span>
Answer:
2 dollars
Step-by-step explanation:
4x2 =8
Solving the quadratic function, it is found that the particle returns to the ground after 7 seconds.
<h3>What is the quadratic function for the particle's height?</h3>
The particle's height after t seconds is modeled by the following equation:
s(t) = -16t² + v(0)t.
In which v(0) is the initial velocity of the particle, which in this problem is of 112 ft/s, hence:
s(t) = -16t² + 112t.
The particle hits the ground when s(t) = 0, hence:
s(t) = 0
-16t² + 112t = 0
-16t(t - 7) = 0.
Hence the non-trivial solution is:
t - 7 = 0 -> t = 7.
The particle returns to the ground after 7 seconds.
More can be learned about quadratic functions at brainly.com/question/24737967
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