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Ksenya-84 [330]
3 years ago
7

PLEASE HURRY !!!! WILL MARK BRAINLIEST !!!!

Mathematics
2 answers:
PIT_PIT [208]3 years ago
7 0
The answer is EGH and EFG
Scrat [10]3 years ago
7 0

Answer:

FGI and HIJ,EGH and HIJ, and EGH and EFG

Step-by-step explanation:

To answer this, you must find if the planes share a common side

just go down the list and you will see that all of them except HIJ and EFG share a common side so they intersect

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PLEASE HELP ASAP 30 POINTS!! Show all work!
Mazyrski [523]

Answer:

D, 6500 increased by 1.4% is 6591 plus another 1.4% which is 6683 and for the last year you add another 1.4% to get the final answer which is D 6,776.84

3 0
3 years ago
Read 2 more answers
The length of a rectangle is the width minus five units.the area of the rectangle is 36 units.what is the width,in units,of the
Andreas93 [3]
Length × Width = Area

-5*Width = 36

Simply divide 36 by 5 to get your answer


Hope that helps!!!!
8 0
3 years ago
What is the measure of XYZ​
lorasvet [3.4K]

Answer:

B

Step-by-step explanation:

The arc XZ is twice the measure of the inscribed angle XYZ , that is

arc XZ = 2 × 60° = 120°

The complete circumference = 360° , thus

arc XYZ = 360° - arc XZ = 360° - 120° = 240° → B

6 0
3 years ago
Read 2 more answers
Howard chose a candy from a bowl with 5 chocolate candies, 4 gummy candies and 6 hard candies. What is Howard's dependent probab
Hatshy [7]

Answer:

8.9%

Step-by-step explanation:

Here, we are to calculate the probability of Howard choosing a chocolate candy followed by a gummy candy.

The probability of selecting a chocolate candy = number if chocolate candy/ total number of candy

Total number of candy = 5 + 4 + 6 = 15

Number of chocolate candy = 5

The probability of selecting a chocolate candy = 5/15 = 1/3

The probability of selecting a gummy candy = number of gummy candies/total number of candies

Number of gummy candy = 4

The probability of selecting a gummy candy = 4/15

The probability of selecting a chocolate candy before a gummy candy = 1/3 * 4/15 = 4/45 = 0.088888888889

Which is same as 8.89 percent which is 8.9% to the nearest tenth of a percent

7 0
3 years ago
In circle A below, chord BC and diameter DAE intersect at F. If arc CD = 46° and arc BE = 78°, what is m_BFE? D B А​
wel

Given:

Consider the below figure attached with this question.

In circle A below, chord BC and diameter DAE intersect at F.

The arc CD = 46° and arc BE = 78°.

To find:

The measure of angle BFE.

Solution:

According to intersecting chords theorem, if two chords intersect inside the circle then the angle on the intersection is the average of intercepted arcs.

Using intersecting chords theorem, we get

m\angle BFE=\dfrac{1}{2}(m(arcCD)+m(arcBE))

m\angle BFE=\dfrac{1}{2}(46^\circ+78^\circ)

m\angle BFE=\dfrac{1}{2}(124^\circ)

m\angle BFE=62^\circ

Therefore, the measure of angle BFE is 62°.

6 0
3 years ago
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